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horrorfan [7]
3 years ago
12

Determine the magnitude of the current flowing through a 4.7 kilo ohms resistor if the voltage across it is (a) 1mV (b) 10 V (c)

4e^-t
Physics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

213 nA

2.13 mA

851e^-t μA

Explanation:

We have a pretty straightforward question here.

Ohms Law states that the current in an electric circuit is directly proportional to the voltage and inversely proportional to the resistance in the circuit. It is mathematically written as

V = IR, since we need I, we can write that

I = V/R

a) at V = 1 mV

I = (1 * 10^-3) / 4.7 * 10^3

I = 2.13 * 10^-7 A or 213 nA

b) at V = 10 V

I = 10 / 4.7 * 10^3

I = 0.00213 A or 2.13 mA

c) at V = 4e^-t

I = 4e^-t / 4.7 * 10^3

I = 0.000851e^-t A or 851e^-t μA

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50 points physics question (multiple choice) Will give brainliest!
Basile [38]

There are two systems that contain only the fundamental frequency and they are the systems C and D.

<h3>What is fundamental frequency?</h3>

The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.

From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.

Learn more about fundamental frequency:brainly.com/question/9424813

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5 0
2 years ago
A ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. What is the average speed of the
antoniya [11.8K]
Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m

The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²

The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s

The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s

Answer: 12.5 m/s

6 0
3 years ago
Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.25 m and finds that it makes 419
Zina [86]

Answer:

g=2406.8m/s^{2}

Explanation:

firstly we have to find the frequency and then the angular frequency.

The frequency will be:

   f=\frac{419}{60} \\f=6.98Hz

The angular frequency is:

ω=2\pi f

ω=2*\frac{22}{7} *6.98

ω=43.88rad /sec

Now we can apply simple pendulum relationship

ω=\sqrt{\frac{g}{l} }

make g the subject of the formula

g=w^{2} l\\g=43.88^{2} *1.25\\g=2406.8m/s^{2}

6 0
3 years ago
Read 2 more answers
A particle experiences constant acceleration for 20 seconds
lisabon 2012 [21]

Answer:

The correct answer is D. s₂=4s₁

Explanation:

The distance of a particle is given by:

s=s_{0}+v_{0} t + \frac{1}{2} a t^{2}

where

s₀ is the initial position when t=0

v₀ is the initial speed when t=0

a is the constant acceleration

t is the time in seconds

Then, the position s₁ is given by:

s_{1} = s_{0}+v_{0} t_{1} + \frac{1}{2} a (t_{1})^{2}

As the particle starts from rest v₀=0 and we consider s₀=0, s₁ will be:

s_{1}= \frac{1}{2} a (t_{1})^{2}

Furthermore, the position s₂ is:

s_{2}= \frac{1}{2} a (t_{2})^{2}

In this case t₁=10 s and t₂=20 s (10 seconds later). In other words t₂=2t₁.

We replace the value of  t₂ in the second equation (s₂):

s_{2}= \frac{1}{2} a (t_{2})^{2} \\ s_{2}= \frac{1}{2} a (2t_{1})^{2} \\ s_{2} = \frac{1}{2} a 2^{2}(t_{1})^{2} \\ s_{2} = \frac{1}{2} a 4 t_{1}^{2}

Finally, we divide s₂ by s₁ to get the ratio:

\frac{s_2}{s_1} =\frac{\frac{1}{2}a4t_{1}^{2} }{\frac{1}{2}at_{1}^{2}} =4

\frac{s_2}{s_1}=4 \\  s_{2} = 4 s_{1}

5 0
3 years ago
How much kinetic energy will an electron gain if it accelerates through a potential difference of 23,000 volts in a cathode ray
Sauron [17]

Answer:

3.68x10-15 J

Explanation:

I hope this is the right answer sorry if im wrong

8 0
2 years ago
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