Using Kepler's 3rd law which is: T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds :
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m
V=IR
I=V/R
R=V/I
these are the realations of voltage ,resistance , and current .
Water cycle basically involves the change of water into liquid to vapour and again to liquid states through a cyclic manner .
The answers are
- Evaporation
- Transpiration
- Condensation
- precipitation
- runoff
- seapage
- ground water
<h2>
Answer:20.97g N,32.63g N</h2>
Explanation:
We consider the forces at the knot.
The vertical forces are
is the vertical component of tension
at the knot.
is the weight of the mass
acting downwards.
The horizontal forces are
is the tension in the rope acting left.
is the horizontal component of tension
acting towards right.
Since the knot has no mass,it is always in equilibrium.
So,the sum of forces acting on it will be zero.
Balancing vertical forces gives,


=
Balancing horizontal forces gives,


