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IrinaVladis [17]
3 years ago
14

If a gas turned into a solid without going through the liquid state and how do you reverse it?

Physics
2 answers:
agasfer [191]3 years ago
4 0

Answer:

put it in a volcano

Explanation:

Pavlova-9 [17]3 years ago
4 0
Deposition is the phase transition in which gas transforms into solid without passing through the liquid phase. Deposition is a thermodynamic process. The reverse of deposition is sublimation and hence sometimes deposition is called desublimation.
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The asteroid belt circles the sun between the orbits of mars and jupiter. one asteroid has a period of 5.0 earth years. assume a
My name is Ann [436]
Using Kepler's 3rd law which is: T² = 4π²r³ / GM 
Solved for r : 
r = [GMT² / 4π²]⅓ 
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds : 
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s 
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m 
8 0
3 years ago
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What is the mathematical relationship between voltage (V), resistance (R), and current (I)? Express your answer as an equation:
Lemur [1.5K]
V=IR
I=V/R
R=V/I
these are the realations of voltage ,resistance , and current .
3 0
4 years ago
Can someone please answer this, ill give you brainliest Would be very appreciated.
mina [271]

Water cycle basically involves the change of water into liquid to vapour and again to liquid states through a cyclic manner .

The answers are

  1. Evaporation
  2. Transpiration
  3. Condensation
  4. precipitation
  5. runoff
  6. seapage
  7. ground water
5 0
2 years ago
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How Many Days Would a Scientist Have To Wait For The Radioactivity To Be 12.5 The Starting Amount
kiruha [24]
They have to wait 18 days.
3 0
4 years ago
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A 25kg mass is suspended at the end of a horizontal, massless rope that extends from a wall on the left and from the end of a se
patriot [66]
<h2>Answer:20.97g N,32.63g N</h2>

Explanation:

We consider the forces at the knot.

The vertical forces are

T_{2}Sin(50^{0}}) is the vertical component of tension T_{2} at the knot.

-25g is the weight of the mass 25Kg acting downwards.

The horizontal forces are

-T_{1} is the tension in the rope acting left.

T_{2}Cos(50^{0}) is the horizontal component of tension T_{2} acting towards right.

Since the knot has no mass,it is always in equilibrium.

So,the sum of forces acting on it will be zero.

Balancing vertical forces gives,

T_{2}Sin(50^{0}})-25g=0

T_{2}=32.63gN

Balancing horizontal forces gives,

T_{2}Cos(50^{0})-T_{1}=0

T_{1}=32.63g\times Cos(50^{0})=20.97gN

7 0
3 years ago
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