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djyliett [7]
3 years ago
7

Which would have a stronger attraction to the nucleus, the outer electrons of a carbon atom, or the outer electrons of an oxygen

atom? Why?
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer: Outer electrons because they revolve around the nucleus and can be multiple more than one

Explanation:

Hope it helps you you

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32
myrzilka [38]

Answer:

0.305 mol

Explanation:

Ca(NO) is not a molecule. I think you meant to type Ca(NO3)2, which is calcium nitrate.

The moles of a compound is equal to is mass divided by its molar mass.

The molar mass of Ca(NO3)2 is 164.09 g/mol.

50.0 / 164.09 = 0.305

6 0
2 years ago
A chemist must dilute 97.1 ml of aqueous magnesium fluoride solution until the concentration falls to 389 microMolarity . He'll
mojhsa [17]

Answer:

0.302L

Explanation:

<em>...97.1mL of 1.21m M aqueous magnesium fluoride solution</em>

<em />

In this problem the chemist is disolving a solution from 1.21mM = 1.21x10⁻³M, to 389μM = 389x10⁻⁶M. That means the solution must be diluted:

1.21x10⁻³M / 389x10⁻⁶M = 3.11 times

As the initial volume of the original concentration is 97.1mL, the final volume must be:

97.1mL * 3.11 = 302.0mL =

0.302L

6 0
3 years ago
How does a system at equilibrium respond to the addition of more reactant
grin007 [14]

Answer:

It favors the forward reaction.

Explanation:

According to Le Chatelier's Principle, when a system at equilibrium suffers a perturbation, the system will react in order to counteract the effect of such perturbation.

If more reactant is added, the system will try to decrease its concentration. It will do so by favoring the forward reaction, decreasing the concentration of the reactant  and increasing the concentration of the products, in order to re-establish the equilibrium.

7 0
4 years ago
The temperature of a freezer started at 18şc. After cooling for a few hours, the freezer had a temperature of –12şc. What is the
andre [41]
20 minus 2 plus 1 equals negative -2000000
8 0
3 years ago
A hot piece of copper was dropped into 155 g of water at 23.6 °C and 2,100 J of energy was transferred to the water. What is the
BlackZzzverrR [31]

Answer:

26.8 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 155 g
  • Energy transferred to the water (Q): 2100 J
  • Initial temperature of the water (T₂): 23.6 °C
  • Final temperature of the water (T₁): ?
  • Specific heat of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C

5 0
3 years ago
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