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djyliett [7]
3 years ago
7

Which would have a stronger attraction to the nucleus, the outer electrons of a carbon atom, or the outer electrons of an oxygen

atom? Why?
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer: Outer electrons because they revolve around the nucleus and can be multiple more than one

Explanation:

Hope it helps you you

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Someone answer? You don’t have to answer both if you don’t know.
natima [27]
I’m not sure what the 6 means, but for the first one, the process being shown is photosynthesis that occurs in a plant. The first two compounds are the reactants. The CO2 is carbon dioxide, and the H2O is water. When these two reactants are put together with some sunlight, they create the products. The C6H12O6 is glucose, and the O2 is oxygen.
4 0
2 years ago
What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of
jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl

58.44 is the molar mass of NaCl

m=0.1711 mol NaCl/2 kg H2O

m=0.085557837

7 0
3 years ago
A chemist adds 0.50L of a 0.485 M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper(II)
den301095 [7]

Explanation:

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

               Number of millimoles = Molarity × Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

             Number of millimoles = Molarity × Volume

                                                 = 0.485 M × 500 mL      

                                                 = 242.5

Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.                                      

4 0
3 years ago
Which energy profile best shows that the enthalpy of formation of cs2 is 89.4 kj/mol?
Kruka [31]
Answer is: B. C(s) + 2S(s) + 89.4 kJ → CS2(l).

Missing question:
A. C(s) + 2S(s) → CS2(l) + 89.4 kJ.
B. C(s) + 2S(s) + 89.4 kJ → CS2(l).
C. C(s) + 2S(s) + 89.4 kJ → CS2(l) + 89.4 kJ.
D. C(s) + 2S(s) → CS2(l).
Because enthalpy of the system is greater that zero, this is endothermic reaction (<span>chemical reaction that absorbs more energy than it releases)</span>, heat is included as a reactant.
5 0
3 years ago
A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?​
Anni [7]

Answer:

<h2>0.14 kg</h2>

Explanation:

The mass of the ball can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

v is the velocity

k is the kinetic energy

From the question we have

m =  \frac{2(3.10)}{ {6.70}^{2} }  =  \frac{6.20}{44.89}  \\  = 0.138115...

We have the final answer as

<h3>0.14 kg</h3>

Hope this helps you

7 0
3 years ago
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