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djyliett [7]
3 years ago
7

Which would have a stronger attraction to the nucleus, the outer electrons of a carbon atom, or the outer electrons of an oxygen

atom? Why?
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer: Outer electrons because they revolve around the nucleus and can be multiple more than one

Explanation:

Hope it helps you you

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Which components of the apparatus affect its motion?
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Answer:

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Explanation:

5 0
3 years ago
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NeTakaya
No, because boats and other mechanical vehicles can spill gas and oil into the freshwater. if the freshwater is scarce already, we should not contaminate it more by risking the gas and oil spills.
7 0
2 years ago
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and
blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon

For Hydrogen:

=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen

For Oxygen:

=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon

For Hydrogen:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen

For Oxygen:

\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen

Thus, the empirical formula is HCO₂

4 0
3 years ago
Which metal will displace nickel in a compound? A. Tin B. Arsenic C. Zinc D. Platinum
Sophie [7]
Which metal will displace nickel in a compound? it zink is the  metal
8 0
3 years ago
Read 2 more answers
What is the oxidation number of each phosphorus atom in H4P2O7
nekit [7.7K]

Answer:

+5

Explanation:

The oxidation number of phosphorus can be obtained as follows:

H4P2O7 = 0

4(+1) + 2P + 7(—2) = 0

4 + 2P —14 = 0

Collect like terms

2P = 14 — 4

2P = 10

Divide both side by 2

P = 10/2

P = +5

The oxidation number of phosphorus is +5

7 0
3 years ago
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