The magnesium atom looses two electrons which are accepted by each of the fluorine atoms. (Option D).
<h3>What is an ionic bond?</h3>
An ionic bond is formed when two ions are formed by the loss or gain electrons. In this case, magnesium has to loose two electrons while fluorine will gain two electrons.
Thus, the correct steps in the formation of an ionic bond between these atoms are A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion (Option D).
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3s it is what it says sorry if this is wrong but I just did a qu like this and that's what it was
Answer: Unstable atoms will lose neutrons and protons as they attempt to become stable, atoms the binding energy is not strong enough to hold the nucleus together
Explanation:
Answer:
Here's what I get
Explanation:
The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:
1. Protonation
The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.
2. Loss of the leaving group
A water molecule leaves in a unimolecular process to form a stable 3° carbocation.
3. Loss of an α-hydrogen
A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.
Empirical formula is the simplest ratio of whole numbers of components making up a compound.
empirical formula can be calculated as follows
C H O
mass 12.0 g 2.00 g 5.33 g
number of moles
12.0 g / 12 g/mol 2.00 g / 1 g/mol 5.33 g / 16 g/mol
= 1.00 mol = 2.00 mol = 0.333 mol
divide by the least number of moles
1.00 / 0.333 2.00 / 0.333 0.333/ 0.333
= 3.00 = 6.01 = 1.00
the number of atoms
C - 3
H - 6
O - 1
empirical formula is C₃H₆O
