The decrease in the freezing point of the solution is −1.86oC.
<h3>What is the decrease in the freezing point?</h3>
Now we know that the freezing point depression of a solid is a colligative property of the solution.
Thus we have that;
ΔT = K m i
ΔT = freezing point depression
K = freezing constant
m = molality of the solution
i = Van't Hoff factor
Thus;
molality = 1 mol/1 Kg = 1 m
ΔT = −1.86oC/m * 1 m * 1
ΔT =−1.86oC
Learn more about freezing point:brainly.com/question/3121416
#SPJ1
Answer:
controlled: 2 drops of food coloring
independent: temperature of water
dependent: rate of diffusion
Explanation:
A controlled variable doesn't change throughout the whole experiment, a independent variable is something being tested, and a dependent variable is the results
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether
As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = 
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
<span>Electrons in a nitrogen-phosphorus covalent bond are not shared equally because nitrogen and phosphorus do not have the same electronegativity. The atoms spend more time around the most electronegative atom nitrogen.</span>
