Answer:
Percent composition of the solution is 26 % of sucrose and 74 % of water
Explanation:
Percent composition is the mass of solute, either of solvent in 100 g of solution.
Mass of solution = Mass of solvent + Mass of solute
Mass of solute = 35 g
Mass of solvent = 100 g
As we know, water density = 1g/mL
So 1g/mL . 100 mL = 100 g
35 g + 100 g = 135 g → Mass of solution
(Mass of solute / Mass of solution) . 100 =
(35 g / 135 g) . 100 = 26 %
(Mass of solvent / Mass of solution) . 100 =
(100 g / 135 g) . 100 = 74 %
Answer:
Volume of HCl require = 6 mL
Explanation:
Given data:
Volume of HCl require = ?
Molarity of HCl solution = 1.60 M
Volume of NaOH = 48.0 mL
Molarity of NaOH = 0.200 M
Solution:
Formula:
M₁V₁ = M₂V₂
By putting values,
1.60 M×V₁ = 0.200 M×48.0 mL
V₁ = 0.200 M×48.0 mL/1.60 M
V₁ = 9.6 M .mL /1.60 M
V₁ = 6 mL
Answer:
the answer to your question is A
No of moles= 88/44 =2
therefore no. of molecules =
therefore no.of molecules= 12.046*10^23
Answer : The molar mass of an acid is 266.985 g/mole
Explanation : Given,
Mass of an acid (HX) = 4.7 g
Volume of NaOH = 32.6 ml = 0.0326 L
Molarity of NaOH = 0.54 M = 0.54 mole/L
First we have to calculate the moles of NaOH.
Now we have to calculate the moles of an acid.
In the titration, the moles of an acid will be equal to the moles of NaOH.
Moles of an acid = Moles of NaOH = 0.017604 mole
Now we have to calculate the molar mass of and acid.
Now put all the given values in this formula, we get:
Therefore, the molar mass of an acid is 266.985 g/mole
