Answer:
The answer is below
Explanation:
one gallon of gasoline produces 9.50 kg of carbon.
The total number of cars = 40 million
Distance covered by each car = 7930 miles
Consumption rate of the cars per miles traveled is 23.6 miles per gallon.
Hence the annual gasoline consumption by all the cars in the United States of America = (total number of cars × Distance covered by each car) ÷ Consumption rate of the cars per miles
annual gasoline consumption by all the cars = (40000000 × 7930 miles) ÷ 23.6 miles/gallon = `1.344067797 × 10¹⁰ gallons
1.344067797 × 10¹⁰ gallons = 
Particles that orbit the nucleus are called electrons.
Explanation: Electrons are negatively charged particles arranged in orbits around the nucleus of an atom and determining all of the atom's physical and chemical properties except mass and radioactivity.
D. She rotated the figure 180 degrees about the origin
This is a PV=nRT problem. So to do this, you are looking for grams. The easiest way to get to grams is to convert moles, so set up the equation looking for n
n=PV/RT
To keep everything consistent with the universal gas constant (0.082057 L atm/mol K), one thing needs to be converted.
To convert 34.0 C to kelvin, just add 273.15. That gets 307.2 with sig figs.
Next, plug everything into your equation
n=(6.22atm)(16.6L)/(0.082057Latm/molK)(307.2K)
Cleaning that up gets you 4.10 moles (again, after sig figs)
Now, you need to convert the 4.10 moles of O2 to grams. To do that, you multiply 4.10 by 31.998 (molar mass of o2) to get 131 g (for a third time, sig figs!)
So, your final answer is 131 g O2
Sorry if any math is wrong, but you should be able to walk yourself through this and other problems now. Hope I helped!
Answer:
<h3>The answer is 0.23 moles</h3>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>0.23 moles</h3>
Hope this helps you
