Question

A sample of krypton gas collected at a pressure of 1.31 atm and a temperature of 26.0°C is found to occupy a volume of 23.3 liters

Answer 1

Mol of Kr gas = 1.244

Further explanation

In general, the gas equation can be written  

PV=nRT

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08205 L.atm / mol K  

T = temperature, Kelvin  

P=1.31 atm

V=23.3 L

T=26+273=299 K

mol of sample :

$\tt n=\dfrac{PV}{RT}=\dfrac{1.31\times 23.3}{0.08205\times 299}=1.244$