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valina [46]
2 years ago
7

Solve for x please help me

Mathematics
1 answer:
koban [17]2 years ago
5 0

Answer:

Step-by-step explanation:

The volume of a prism is V = Bh, where B is the area of the base shape and h is the height of the prism. Find the area of the parallelogram that is the base, length x width, then multiply this by the height of the prism. l x w x h.

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∠A and \angle B∠B are vertical angles. If m\angle A=(7x-6)^{\circ}∠A=(7x−6)
Nikolay [14]

keeping in mind that vertical angles are always congruent.

\stackrel{\measuredangle A}{7x-6}~~ = ~~\stackrel{\measuredangle B}{8x-27}\implies -6=x-27\implies 21=x~\hfill \underset{\measuredangle B}{\stackrel{8(21)~~ - ~~27}{141}}

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QUICK 64 Divded by 8
ch4aika [34]

Answer:

8! 8x8=64 lol

Step-by-step explanation:

Hope this helps, And have a good day!

6 0
3 years ago
What are the coordinates of the inflection point on the graph of y=(x+1)arctanx
Dennis_Churaev [7]

Inflection point is the point where the second derivative of a graph is zero.

y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2

Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2

Therefore, E(1, pi/2).


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0
3 years ago
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