Considering that the powers of 7 follow a pattern, it is found that the last two digits of 
are 43.
<h3>What is the powers of 7 pattern?</h3>
The last two digits of a power of 7 will always follow the following pattern: {07, 49, 43, 01}, which means that, for 
, we have to look at the remainder of the division by 4:
- If the remainder is of 1, the last two digits are 07.
- If the remainder is of 2, the last two digits are 49.
- If the remainder is of 3, the last two digits are 43.
- If the remainder is of 0, the last two digits are 01.
In this problem, we have that n = 1867, and the remainder of the division of 1867 by 4 is of 3, hence the last two digits of are 43.
More can be learned about the powers of 7 pattern at brainly.com/question/10598663
I need to know how long each section is or this is unsolvable.
Or how much length in piping is needed
Answer:
x^3 + x^2 + 4x - 20.
Step-by-step explanation:
I have assumed there is a + between the 3x and the 10.
f(x) * g(x)
= (x^2 + 3x + 10)(x - 2)
= x^3 + 3x^2 + 10x - 2x^2 - 6x - 20
= x^3 + x^2 + 4x - 20.
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
