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7nadin3 [17]
3 years ago
11

The source of thermal energy that an internal combustion engine uses is _____

Chemistry
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

the answer is coal gas

Explanation:

they were used for transportation

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For multiple covalent bonds to form in molecules the molecules must contain carbon nitrogen or​
Stella [2.4K]

For multiple covalent bonds to form in molecules, the molecules must contain carbon nitrogen or​ oxygen.

<u>Explanation:</u>

  • Think about carbon dioxide (CO2). If every oxygen atom imparts one electron to the carbon molecule, there will be 6 electrons in carbon particle and 7 electrons in every oxygen atom. This doesn't give the carbon atom as a total octet.
  • Sometimes more than one set of electrons is shared between two atoms. In carbon dioxide, a second electron from every oxygen atom is likewise imparted with the central carbon atom, and the carbon particle imparts one more electron with every oxygen atom.
  • Two sets of electrons shared between two atoms make a double bond between the atoms. A few particles contain triple bonds, covalent bonds in which three sets of electrons are shared by two atoms.

7 0
3 years ago
PLEASE HELP BEFORE 7 A.M. PACIFIC TIME <br> SEE ATTACHED.
anastassius [24]
For i: 33mL
For ii: 87-88mL
For iii:22.3mL
5 0
3 years ago
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Can someone give me an example of balancing equations with a solution that is simple?​
Monica [59]

Explanation:

H _{2}O _{2(aq)} →H _{2}O _{(l)}  + O _{2}(g) \\ solution  : 2 \:  and\: 2

6 0
3 years ago
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A mixture of methanol and methyl acetate contains 15.0 wt% methanol.
Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h

5 0
3 years ago
The pressure of 5.00 L of gas increases from 1.50 atm to 1240 mmHg. What is the final volume of the gas, assuming constant tempe
Vsevolod [243]
(P1)(V1)=(P2)(V2)
(1.50)(5.00)=(1240/760)(V2)
(7.5)/(1240/760)=V2
V2=4.596774194 L
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