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3 years ago

13

Match the formula to the correct name. (3 points) 1. LiClO4 2. LiCl 3. LiClO2 a. Lithium perchlorate b. Lithium chloride c. Lith

ium chlorite

2 answers:

Sedaia [141]3 years ago

8 0

One is A, two is C, three is B.

svp [43]3 years ago

5 0

Answer: the answer to number 1 is a. number 2 is b. number 3 is c.

Explanation:

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¿Cómo se clasifican las disoluciones acuosas?

Lilit [14]

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3 0

2 years ago

A student weighed out a 2.055 g sample of a cobalt chloride hydrate, ConClmpH2O, where n, m, and p are integer values to be dete

topjm [15]

The given mass of cobalt chloride hydrate = 2.055 g

A sample of cobalt chloride hydrate was heated to drive off waters of hydration and the anhydrate was weighed.

The mass of anhydrous cobalt chloride = 1.121 g anhydrate.

The mass of water lost during heating = 2.055 g - 1.121 g = 0.934 g

Converting mass of water of hydration present in the hydrate to moles using molar mass:

Mass of water = 0.934 g

Molar mass of water = 18.0 g/mol

Moles of water = $0.934 g * \frac{1 molH_{2}O }{18 g H_{2}O } =0.0519 mol H_{2}O$

8 0

2 years ago

Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to

denis-greek [22]

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒ Mass of solution = $Mass \ of \ (NaCl+H_2O)$

= $51.56+164.2$

= $215.76 \ g$

hence,

⇒ $Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100$

$=\frac{51.56}{215.76}\times 100$

$=23.896 \ percent$

4 0

2 years ago

Which type of scientist would most likely study how electricity could be

miv72 [106K]

Answer:

A physicist

Explanation:

Physics is that aspect of science that deals with nature and matter in relation to energy. Electricity is a source for energy

7 0

1 year ago

How many grams of oxygen are there in 45.7 grams of Ba(NO2),?

Flauer [41]

I’m assuming you mean barium nitrite, Ba(NO2)2.

First convert grams of Ba(NO2)2 to moles using the molar mass of Ba(NO2)2. Then use the mole ratio of 4 moles of oxygen per 1 mole of Ba(NO2)2 to convert to moles of oxygen. Then use the molar mass of oxygen to convert to grams of oxygen.

45.7 g Ba(NO2)2 • 1 mol Ba(NO2)2 / 229.35 g Ba(NO2)2 • 4 mol O / 1 mol Ba(NO2)2 • 16.0 g O / 1 mol O = 12.8 g oxygen

4 0

2 years ago