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Hatshy [7]
2 years ago
15

Calculate the quantity of energy released when 783 g of steam condenses. (show work)

Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
7 0

Answer:

firstark as brainliest

Explanation:

please

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Atomic number is equal to protons and electrons, so the answer is 5
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The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell
tankabanditka [31]

Explanation:

In a voltaic cell, oxidation reaction occurs at anode whereas reduction reaction occurs at the cathode.

Hence, the half-cell reaction taking place at anode and cathode will be as follows.

At anode (Oxidation) : Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-} ...... (1)

At cathode (Reduction) : Ag^{+}(aq) + 1e^{-} \rightarrow Ag(s)

So, in order to balance the half cell reactions, we multiply reduction reaction by 3. Hence, reduction reaction equation will be as follows.

              3Ag^{+}(aq) + 3e^{-} \rightarrow 3Ag(s)  ........ (2)

Therefore, overall reaction will be sum of equations as (1) + (2). Thus, net reaction equation is as follows.

      Cr(s) 3Ag^{+}(aq) \rightarrow Cr^{3+}(aq) + 3Ag(s)          

         

6 0
3 years ago
How many mole of ZnCl2 will be produced from 55.0 g of Zn, assuming HCL is available in excess
Ilia_Sergeevich [38]

Answer:

0.84 mol

Explanation:

Given data:

Moles  of ZnCl₂ produced = ?

Mass of Zn = 55.0 g

Solution:

Chemical equation:

2HCl + Zn  →  ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 55.0 g/ 65.38 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of Zn with ZnCl₂ from balance chemical equation.

                                      Zn          :             ZnCl₂

                                         1          :               1

                                      0.84       :           0.84

So from 55 g of Zn 0.84 moles of zinc chloride will be produced.

8 0
3 years ago
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