The true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.
<h3>What is true about the given reaction?</h3>
The given reaction shows a reaction between A and B to form CD
The reaction is a reversible reaction.
A reversible reaction is a reaction which can proceed in either of two ways where the reactants can react to form the product and also the products an break down to form the reactants.
In the reaction given, as the concentration of A and b decreases, the concentration of CD increases and vice versa.
At equilibrium, the rate of formation of CD is equal to the the rate of decomposition of CD.
Therefore, the true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.
In conclusion, a reaction at equilibrium has the forward and backward reactions occurring at the sane rate.
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Answer:
They are both listed under group 11 on the periodic table and both are highly conductive of electricity
Explanation:
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Answer:
You are the Cobalt
Explanation:
The least massive metalloid in the fourth period is Germanium, and it have 32 protons. If you have 5 less protons: 32 - 5 = 27 protons. The element with 27 protons is Cobalt
Answer:
The answer to your question is 0.64 M
Explanation:
Data
Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g
volume = 25 ml
Molarity = ?
Process
1.- Calculate the molar weight of Sucrose
C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)
= 144 + 22 + 176
= 342 g
2.- Calculate the moles of sucrose
342 g ------------------ 1 mol
7.633 g --------------- x
x = (7.633 x 1) / 342
x = 0.0223 moles
3.- Calculate the molarity
Molarity = moles / volume (L)
Molarity = 0.0223 / 0.035
Molarity = 0.64
The enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Potassium trioxonitrate (V) KNO₃(s) is a strong oxidizing solid substance that when dissolved in water changes to aqueous solution.
In its aqueous solution state, the randomness of molecules increases as a result of that the entropy will also increase leading to the positive state of the entropy.
Similarly, provided that the solution becomes quite cold to the touch, the enthalpy is also in it positive state.
Therefore, we can conclude that the enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
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