Answer:
5.916x10⁻³ mol OH⁻
Explanation:
The reaction that takes place is:
- H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
First we <u>calculate the added moles of each reagent</u>, using the <em>given volumes and concentrations</em>:
- H₂SO₄ ⇒ 0.144 M * 27.55 mL = 3.967 mmol H₂SO₄
- KOH ⇒ 0.316 M * 43.84 mL = 13.85 mmol KOH
Now we<u> calculate how many KOH moles reacted with 3.967 mmol H₂SO₄</u>:
- 3.967 mmol H₂SO₄ * = 7.934 mmol KOH
Finally we calculate how many OH⁻ moles remained after the reaction
- 13.85 mmol - 7.934 mmol = 5.916 mmol OH⁻
- 5.916 mmol / 1000 = 5.916x10⁻³ mol OH⁻
cis-2- butene-1,4-dioic acid and trans-2- butene-1,4-dioic acid are the 2 isomers with the molecular formula C₄H₄O₄.
<u>Explanation:</u>
Isomers are the structures having the same molecular formula but their is a difference in their structural formula and this concept is known as isomerism.
Here we have the molecular formula C₄H₄O₄ and it may be dicarboxylic acid and it may be exist as geometrical isomers as cis-2- butene-1,4-dioic acid and trans-2- butene-1,4-dioic acid.
The isomers are given.
Answer:
Aluminium (Al): (3*2)+(5*2)=16
Sulphor (S): (3*1)=3
Oxygen (O): (4*3)+(3*1)=15
The valency of nitride and magnesium is incorrect