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fomenos
3 years ago
11

Adams contain charged particles called protons and electrons. Each proton has a charge of +1 and each electron has a charge of -

1 sulfur ion has 16 protons and 18 electrons find the net charge each proton has a charge of +1 and each electron has a charge of -1 a sulfur ion has 16 protons and 18 electrons find the net charge
Chemistry
2 answers:
solniwko [45]3 years ago
5 0

16 protons and 18 electrons gives the atom a -2 charge because there are 2 more electrons than protons. If it were 16 protons and 16 electrons, the charge would be 0 or neutral.

Alex787 [66]3 years ago
4 0

Answer:

The net charge will be -2

Explanation:

Atoms are composed of several types of particles, among which are:

Neutrons: They have no electric charge, that is to say that their charge is zero, and they are part of the nucleus of the atom. The charge of a neutron is 0.

Protons They have a positive electrical charge and, together with the neutrons, constitute the nucleus of the atom. The charge of a proton is +1.

Electrons They have negative electrical charge and revolve around the nucleus of the atom. The charge of an electron is −1.

The total charge of an atom depends on the number of protons (with positive charges) and electrons (with negative charges) that compose it. For example, by joining a proton and an electron, a 0 charge is obtained, because the positive charge of the proton is canceled with the negative charge of the electron. So, the total charge of an atom is the sum of the number of protons and electrons.

So, in this case, if the sulfur ion has 16 protons and 18 electrons, the net charge will be the sum of 16 positive charges and 18 negative charges, resulting in a net charge of -2.

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While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting e
sp2606 [1]

The question is incomplete, here is the complete question:

While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene with water vapor at elevated temperatures.

A chemical engineer studying this reaction fills a 1.5 L flask at 12°C with 1.8 atm of ethylene gas and 4.7 atm of water vapor. When the mixture has come to equilibrium she determines that it contains 1.16 atm of ethylene gas and 4.06 atm of water vapor.

The engineer then adds another 1.2 atm of ethylene, and allows the mixture to come to equilibrium again. Calculate the pressure of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits.

<u>Answer:</u> The partial pressure of ethanol after equilibrium is reached the second time is 1.0 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of ethylene gas = 1.8 atm

Initial partial pressure of water vapor = 4.7 atm

Equilibrium partial pressure of ethylene gas = 1.16 atm

Equilibrium partial pressure of water vapor = 4.06 atm

The chemical equation for the reaction of ethylene gas and water vapor follows:

                     CH_2CH_2(g)+H_2O(g)\rightleftharpoons CH_3CH_2OH(g)

<u>Initial:</u>                  1.8                4.7

<u>At eqllm:</u>           1.8-x             4.7-x

Evaluating the value of 'x'

\Rightarrow (1.8-x)=1.16\\\\x=0.64

The expression of K_p for above equation follows:

K_p=\frac{p_{CH_3CH_2OH}}{p_{CH_2CH_2}\times p_{H_2O}}

p_{CH_2CH_2}=1.16atm\\p_{H_2O}=4.06atm\\p_{CH_3CH_2OH}=0.64atm

Putting values in above expression, we get:

K_p=\frac{0.64}{1.16\times 4.06}\\\\K_p=0.136

When more ethylene is added, the equilibrium gets re-established.

Partial pressure of ethylene added = 1.2 atm

                     CH_2CH_2(g)+H_2O(g)\rightleftharpoons CH_3CH_2OH(g)

<u>Initial:</u>                2.36             4.06               0.64

<u>At eqllm:</u>           2.36-x        4.06-x             0.64+x

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0.136=\frac{(0.64+x)}{(2.36-x)\times (4.06-x)}\\\\x=0.363,13.41

Neglecting the value of x = 13.41 because equilibrium partial pressure of ethylene and water vapor will become negative, which is not possible.

So, equilibrium partial pressure of ethanol = (0.64 + x) = (0.64 + 0.363) = 1.003 atm

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