Answer:
<h2>c. x = -4 or x = 9</h2>
Step-by-step explanation:

Domain:

solution:

use <em>(a - b)(a + b) = a² - b²</em>

multiply both sides by (x - 3) ≠ 0

cancel (x - 3)

subtract
from both sides

cross multiply

use FOIL

subtract 4x from both sides

combine like terms

change the signs

The product is 0 if one of the factors is 0. Therefore:

<em>add 9 to both sides</em>

<em>subtract 4 from both sides</em>

Answer:
x y
0 -1
-1 0
-8 7
Step-by-step explanation:
y = -x - 1
when x = 0, y = -1
when y = 0
0 = -x - 1
x = -1
when x = -8,
y = -(-8) - 1
y = 7
The number ... n
one quarter of the number ... 1/4 of n = 1/4 * n
one third of the number ... 1/3 of n = 1/3 * n
one quarter of the number is subtracted from one third of the number ... 1/3 * n - 1/4 * n
the result is 7 ... = 7
We can put it together:
1/3 * n - 1/4 * n = 7
4/12 * n - 3/12 * n = 7
1/12 * n = 7 /*12
n = 7 * 12
n = 84
The number you are looking for is 84.
About 750 different permutations
Answer: b = 2a
Step-by-step explanation:
<u>Original equation</u>
a = (1/2) b
<u>Multiply 2 on both sides</u>
a * 2 = (1/2) b * 2

Hope this helps!! :)
Please let me know if you have any quesitons