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Arte-miy333 [17]
3 years ago
7

What is the chemical name of the compound represented by the formula Ni2O3? Use the list of polyatomic ions and the periodic tab

le to help you answer.
Chemistry
2 answers:
bearhunter [10]3 years ago
5 0
The chemical name is nickel (III) oxide .
LuckyWell [14K]3 years ago
4 0

Answer : The chemical name of the compound Ni_2O_3 is, nickel(III)oxide.

Explanation :

The rules for naming the chemical name of the compound :

  • First element in the formula is named first and keep its element name.
  • Gets a prefix if there is a subscript on it.
  • Written the oxidation state by the us of roman numeral.
  • Second element is named second.
  • Use the root of the element name plus suffix (-ide).
  • Always use a prefix on the second element.

In the given compound, the nickel is the cation and first element in the formula and the oxidation state of nickel is, (+3). The second element is oxygen which is named as oxide.

Thus, the chemical name of the compound Ni_2O_3 is, nickel(III)oxide.

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Look at the dots around each symbol and the energy levels from the resources above;
Anton [14]

Hello! Here's the answer I was able to come up with:

<em>Why does Na have only one dot?</em>

Sodium, or Na, has only one valence electron.  (This makes the atom tend to participate in ionic bonding and "give" its single valence electron to an atom like chlorine.)

<em>Why do none of these diagrams show more than 8 dots?</em>

It is physically impossible for an atom to have more than 8 electrons in its valence layer, according to the Octet Rule.

<em>What relationship do you notice between the dots in these two charts?</em>

The dot diagram for each element represents the number of electrons each element will have in its outermost, or valence, shell. (2-8-8)

<em>The number of dots that hydrogen and helium have in their dot diagram is the same as the number of electrons shown for them on the Periodic Table. Why?</em>

An atom can have a maximum of two electrons in its innermost layer. Hydrogen and helium have only one and two electrons, respectively, so they don't have enough electrons to actually have more than one layer. Therefore, their outermost layer is, in fact, their only layer. This is why the number of dots that hydrogen and helium have in their dot diagram is the same as the number of electrons shown for them on the Periodic Table.

Don't copy this word for word! You will most likely be in trouble for plagiarism.  Instead, rewrite these ideas in your own words, or paraphrase. Good luck, and I know you can do it! ♥  

6 0
3 years ago
Help please! I'd appreciate it 
babymother [125]

Answer:

16.56 g

Explanation:

Mass is the production of Volume and Density.

m = V. d = 6 × 2.76 = 16.56 g

6 0
3 years ago
What is a daughter cell
Leno4ka [110]
The cells that result from the reproductive division of one cell during mitosis or meiosis
6 0
3 years ago
Read 2 more answers
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
3 years ago
How do you find the molecular formula from the empirical formula?
miskamm [114]
To find them you would have numbers of the elements in percentage or grams then you divide them by their molar mass to get their moles. From there you divide by the smallest number. Round it to two or one sig fig. If you have a number that is for ex. 2.5 you multiply it by 2 to make it whole as well the other whole numbers. Then to find the molecular formula the problem must give you another molar mass and using your empirical formula convert it to its molar mass then you divide them, larger number over smaller number. You should get a number round it to 1 sig fig. Now you use that number and multiply the subscripts on the empirical formula to get the molecular formula.
7 0
3 years ago
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