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Arte-miy333 [17]

3 years ago

7

What is the chemical name of the compound represented by the formula Ni2O3? Use the list of polyatomic ions and the periodic tab

le to help you answer.

2 answers:

bearhunter [10]3 years ago

5 0

The chemical name is nickel (III) oxide .

LuckyWell [14K]3 years ago

4 0

Answer : The chemical name of the compound $Ni_2O_3$ is, nickel(III)oxide.

Explanation :

The rules for naming the chemical name of the compound :

First element in the formula is named first and keep its element name.
Gets a prefix if there is a subscript on it.
Written the oxidation state by the us of roman numeral.
Second element is named second.
Use the root of the element name plus suffix (-ide).
Always use a prefix on the second element.

In the given compound, the nickel is the cation and first element in the formula and the oxidation state of nickel is, (+3). The second element is oxygen which is named as oxide.

Thus, the chemical name of the compound $Ni_2O_3$ is, nickel(III)oxide.

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Instant cold packs, often used to ice athletic injuries on the field, contain ammonium nitrate and water separated by a thin pla

RSB [31]

<u>Answer:</u> The enthalpy change of the reaction is -27. kJ/mol

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 25.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{25.0mL}\\\\\text{Mass of water}=(1g/mL\times 25.0mL)=25g$

To calculate the heat released by the reaction, we use the equation:

$q=mc\Delta T$

where,

q = heat released

m = Total mass = [1.25 + 25] = 26.25 g

c = heat capacity of water = 4.18 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(21.9-25.8)^oC=-3.9^oC$

Putting values in above equation, we get:

$q=26.25g\tiimes 4.18J/g^oC\times (-3.9^oC)=-427.9J=-0.428kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ammonium nitrate = 1.25 g

Molar mass of ammonium nitrate = 80 g/mol

Putting values in above equation, we get:

$\text{Moles of ammonium nitrate}=\frac{1.25g}{80g/mol}=0.0156mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = -0.428 kJ

n = number of moles = 0.0156 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{-0.428kJ}{0.0156mol}=-27.44kJ/mol$

Hence, the enthalpy change of the reaction is -27. kJ/mol

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wariber [46]

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What characteristics are used to clarify an area as a wetland?

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3 years ago

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Keith_Richards [23]

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