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3 years ago

Does anyone know how to make this a longer sentence?

Chemistry

2 answers:

Nadusha1986 [10]3 years ago

7 0

Answer:

First, you have to analyze your problem or question. After you research and collect data about your topic, create a hypothesis to test to try and find the answer. After testing your hypothesis, come up with a conclusion based on the results.

frutty [35]3 years ago

3 0

The other one is correct and have a good day

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3 years ago

A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.

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R1/R2 = √MM2/√MM1
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3 years ago

Read 2 more answers

Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)

Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)

We can write the above reaction in two reactions, one for oxidation and the other for reduction:

Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻ (2)

Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)

We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).

We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.

In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).

Therefore, the reducing agent in reaction (1) is lithium (Li).

Learn more here:

brainly.com/question/10547418?referrer=searchResults

brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

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2 years ago