Answer:
PART A
Explanation:
3. A cylinder of compressed gas has a pressure of 4.882 atm on one day. The next
day, the same cylinder of gas has a pressure of 4.690 atm, and its temperature is
8°C. What was the temperature on the previous day in °C? Ans: 20°C.
Answer:
first
Explanation:
Assets = Equity + Liability. ...
Assets = Liabilities + Shareholder's Equity.
then ans will be in your feet it's east
The trough and the hill part
STP is the abbreviation of standard condition for temperature and pressure which is 273.15K temperature and 1.013× 10^5 Pa pressure. Since the pressure and temperature changes, I assume the question would ask about the result of the volume. The temperature used in ideal gas should be Kelvin, so 27 Celcius would be 300.15K.
The calculation would be
PV=T
V=T/P
V2/V1= T2*P1/T1*P2
V2/V1=273.15K* 90^10^3Pa/ 300.15K * 1.013× 10^5 Pa
V2= 0.81904 * 51.7ml
V2= 42.34ml
To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:
Clearing the specific heat of the unknown substance:
