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tester [92]
2 years ago
14

When copper is changed to copper(II) nitrate by the nitric acid, it is an example of a(n) ______-_______ reaction. (two words, i

nclude the hyphen with no spaces)
Chemistry
1 answer:
Nataly_w [17]2 years ago
5 0

Answer:

oxidation- reduction

Explanation:

where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent

<h2>Oxidize: copper = Cu+2</h2>
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They both build up to form electricity
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Explanation:

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2 years ago
The mass of .10 moles of iron is:
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Answer:

<em>so mass in gram=560grams</em>

Explanation:

number of moles=10moles

molar mass=56grams/moles

mass in gram of Fe=?

as we know that

number of moles=\frac{mass in gram}{molar mass}

<em>evaluating the formula</em>

<em>number of moles×molar mass=mass in gram</em>

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<em>mass in gram=560grams</em>

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8 0
3 years ago
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What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of
jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl

58.44 is the molar mass of NaCl

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7 0
3 years ago
P 4 + 5O 2 P 4 O 10 , 1.5 moles of product was made in 30 seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min
Airida [17]

Answer: 850.0 g/min.

Explanation:

  • The rate of the reaction = (ΔC/Δt) where,

ΔC is the change in concentration of reactants or products.

Δt is the change in time of the reaction proceeding.

  • The rate is needed to be calculated in (g/min).
  • We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
  • mass (g) = n x molar mass,
  • n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
  • m = 1.5 x 283.88 = 425.82 g.
  • ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
  • The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.

<em>can be approximated to 850.0 g/min.</em>

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3 years ago
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