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mestny [16]
3 years ago
13

Match the word to the part of the wave. (Lesson 4.02)

Chemistry
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

1 A. Wavelength 2. B. Crest 3. C. Amplitude 4. D. Trough

Explanation:

I cant really give an explanation but I hope it helps

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N₂(g) + 3H₂(g) → 2NH3(g)
Anna71 [15]

Answer:

93.5 moles N₂

Explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

8 0
2 years ago
Which answer best explains one of the reasons that oceans are salty?
Tatiana [17]

Answer:

(D) Water from streams and rivers carry salt to the ocean

Explanation:

Hope this helps!

8 0
3 years ago
The gravitational force of Earth is causing volcanoes on the moon.
yan [13]
This is true, the force can bring land up at ease
7 0
4 years ago
Is the boiling point of oxygen higher than nitrogen's
PSYCHO15rus [73]
The boiling point of oxygen is higher than nitrogen's boiling The reason the boiling point of O2 is higher is not because of increased van der Waals interactions, but simple physics. The mass of a molecule of O2 is greater than that of a molecule of N2, so the molecule of O2 traveling at a speed sufficient to break out of the liquid phase has a greater kinetic energy than an analogous N2 molecule. The net effect is that more energy must be distributed throughout a sample of O2 to achieve a given vapor pressure (in this case equal to atmospheric pressure) than for a sample of N2. More energy means greater temperature.
8 0
4 years ago
Calculate the pressure exerted by 1.0 mol of C6H6behaving as a)a perfect gas and b) a van der Waals gas when it is confined unde
Sholpan [36]

Answer:

The detailed calculation is shown in the attached file.

last condition (1000 K in 150.000 dm3) will have the least deviations and it is the condition where real gas will behave as ideal gases

Explanation:

Real gas behave more ideally or they tend towards ideality when there is the least deviation, or their inter-molecular forces between their molecules are mainly responsible for their deviations as such gases with the strongest intermolecular forces shows the strongest deviations. As such, when their is an increase in temperature and volume and a decrease in pressure, real gas tends towards ideal gas in this case.

From the three conditions given, it is obvious that the last condition(1000 K in 150.000 dm3)  will have the least deviations.

6 0
4 years ago
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