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3 years ago

Match the word to the part of the wave. (Lesson 4.02)

Chemistry

1 answer:

Alenkinab [10]3 years ago

3 0

Answer:

1 A. Wavelength 2. B. Crest 3. C. Amplitude 4. D. Trough

Explanation:

I cant really give an explanation but I hope it helps

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How to balance the equation Mg2+HO2=Cu3O+H2<br><br>

Mariulka [41]

I think the answer is 2Mg + H2O4 = Cu12O4 + 2H

I’m really not sure though so it might be wrong… I’m not the best at balancing equations lol

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2 years ago

(IMAGE ATTACHED)<br>Help plssss this is due in 3 hours<br>

Natasha2012 [34]

Answer:

Acceleration:

Speed/Time

Change in speed or velocity over a specific amount of time

Speed:

Distance/Time

Change in distance over a specific amount of time

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3 years ago

Which of the following is an important application of hydrogen bonding

Andrews [41]

Hydrogen bonding is important because it is crucial to all life on Earth. Here are three reasons why hydrogen bonding is important. DNA has a double-helix structure because hydrogen bonds hold together the base pairs in the middle. Without hydrogen bonds, DNA would have to exist as a different structure.

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3 years ago

Read 2 more answers

First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it ta

Klio2033 [76]

Rate equation for first order reaction is as follows:

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}$

Here, k is rate constant of the reaction, t is time of the reaction, $A_{0}$ is initial concentration and $A_{t}$ is concentration at time t.

The rate constant of the reaction is $0.1 day^{-1}$ .

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days$

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days$

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c) Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{0.1}=69.09 days$

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

5 0

3 years ago

Is lithium a metal metalloid or non metal

KiRa [710]

Answer:

Metal

Explanation:

Lithium (Li), chemical element of Group 1 (Ia) in the periodic table, the alkali metal group, lightest of the solid elements. The metal itself—which is soft, white, and lustrous—and several of its alloys and compounds are produced on an industrial scale.

Atomic number: 3

Atomic weight: 6.941

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3 years ago