Based on the information provided,
The evidence that this nuclear reaction reaction represent transmutation is it formed different elements
hope this helps
Subtract the mass of the solute from the whole solution volume.
Molarity, percent by mass, and percent by volume are all ways to represent concentration.
By dividing the number of moles by the number of liters of water utilized in the solution, we can compute the molar concentration. Here, for instance, 1.25 L of water has entirely dissolved the acetic acid. In order to determine the molar concentration, which is 0.1332 M, divide 0.1665 moles by 1.25 L. A titration is a method for figuring out the concentration of an unknown solution by using a solution with known concentration.
Finding the concentration for each sample's absorbance on the standard curve is the first step in calculating the sample concentration based on the standard curve. The next step is to multiply the concentration by the dilution factor for each sample.
Learn more about concentration here brainly.com/question/10703427
#SPJ4.
Answer:
atoms are too small to be seen under a microscope
Explanation:
scientists have been always making research on atomic structure which cannot be directly looked through a microscope
Answer:
Ksp= 7.98 × 10^-13
Explanation:
According to the question, we are to calculate the solubility constant (Ksp) of Zinc carbonate (ZnCO3) in a dissolved solution.
The equilibrium of the reaction is:
ZnCO3 (aq) ⇌ Zn2+ (aq) + CO32- (aq)
According to this; 1 mole of Zinc carbonate (ZnCO3) dissolves to give 1 mole of Zinc ion (Zn2+) and 1 mole of carbonate ion (CO32-).
This illustrates that:
(Zn2+) = 1.12 x 10-4 g/L
(CO32-) = 1.12 x 10-4 g/L
However, 1.12 x 10-4 g/L is the solubility in mass concentration of ZnCO3, we need to convert it to molar concentration in mol/L by dividing by the relative molar mass of ZnCO3.
To calculate the molar mass of ZnCO3, we say:
Zn (65.4) + C (12) + 03 (16×3)
= 65.4+12+48
= 125.4g/mol.
Hence, molar concentration= 1.12 x 10-4 g/L / 125.4 g/mol
= 8.93 × 10^-7 mol/L.
Therefore;
Zn2+) = 8.93 x 10-7 mol/L
(CO32-) = 8.93 x 10-7 mol/L
Ksp = [Zn2+] [CO32-]
Ksp = (8.93 x 10-7) × (8.93 x 10-7)
Ksp = 7.98 × 10^-13
Given that the drum is replaced each time before sampling, the selections are independent events. Then, the probability of the combined event is the product of each probability: (50/5000) * (50/5000) * (50/5000) = (1/100)^3 = 0.000001