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2 years ago

13

What can do ,when the solution remain in the jet/ nozzle of the pipette?

1 answer:

lutik1710 [3]2 years ago

5 0

ans is opt (b)

Explanation:

the pippet reading is already adjusted accordingly so there is no need to blpw out the last drop ylthe reading will be accurate anyway

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Which of the following apply to diffusion. Select all that apply. Solids can diffuse in liquids. Liquids can diffuse in liquids.

e-lub [12.9K]

Correct answers are:

Solids can diffuse in liquids. Think of a sugar cube sitting at the bottom of a cup of tea.
Liquids can diffuse in liquids. Think of a drop of food colouring in water
It is the process of intermingling atoms from one substance into another.

The other answers are <em>incorrect</em> because:

Gas molecules are far apart and diffuse rapidly.
A solid can diffuse into another solid. Pure lead can diffuse into gold, and pure gold can diffuse into lead.

3 0

3 years ago

Read 2 more answers

Please match the orbital type with the correct number of orbitals

saul85 [17]

Hi there!

p = e-3
s = f-1
f = i-7
d = g-5

Hope that helps!
Brady

7 0

3 years ago

When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2

MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

$= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}$

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is $\Delta \ T_f = T_{solvent}- T_{solution}$

$\Delta \ T_f = 2.9 ^0 \ C$

Using the depression in freezing point, the molar depression constant of the solvent $K_f = \dfrac{\Delta T_f}{m}$

$K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}$

$K_f = 4.82 ^0 C / m}$

The freezing point of the solution $\Delta T_f = T_{solvent} - T_{solution}$

$\Delta T_f = 7.3^ 0 \ C$

The molality of the solution is:

$= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}$

Molar depression constant of solvent X, $K_f = 4.82 ^0 \ C/m$

Hence, using the elevation in boiling point;

the Vant'Hoff factor $i = \dfrac{\Delta T_f}{k_f \times m}$

$i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}$

$\mathbf {i = 1.51 }$

3 0

3 years ago

Help plz I rly. Need it

babymother [125]

Answer:

It should be D.

Explanation:

3 0

3 years ago

What is the correct order of earths six convection cells , from the North Pole to the South Pole

makkiz [27]

<span>polar, Hadley, Ferrel, polar, Hadley, Ferrel. I hope this helps you.</span>

4 0

3 years ago