The electron configuration of V³⁺ is [Ar]
. The ion is paramagnetic because it has two unpaired electrons
<h3>
What is paramagnetic?</h3>
- A weak magnetic field supplied externally can weakly attract some materials, which then create internal magnetic fields that are directed in the same direction as the applied magnetic field. This phenomenon is known as paramagnetic.
- Diamagnetic materials, in contrast, are attracted to magnetic fields and produce induced magnetic fields that are directed in the opposite direction from the applied magnetic field.
- The majority of chemical elements and some compounds are considered to be paramagnetic materials.
- Paramagnetic materials have a relative magnetic permeability that is somewhat more than 1, which makes them attracted to magnetic fields.
- The applied field induces a linearly decreasing magnetic moment that is relatively weak.
- Modern experiments on paramagnetic materials are frequently done with a sensitive analytical balance since it typically requires a sensitive analytical balance to identify the effect.
To learn more about paramagnetic with the given link
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109.5
tetrahedral shape:
number of electron pair = 4,
number of bonded pair = 4,
number of lone pair = 0.
ANWERS ~
We know that :
1 cal (th) = 4.184 J
1 J = 0.2390057361 cal (th) , so :
•55.2 j to cal > 13.193116635 cal
•110 call > 460.24 joule
•65 kj > divide the energy value by 4.184
= 15.535 kilocalories calorie (IT)
——————
Converting form C to F > (F-32)*5/9Understand it better if we have Fahrenheit just add to the equation mentioned to find Celsius.
+to find F to C> (9/5*C)+32
•425 Fahrenheit = (425- 32) × 5/9 =218.33333333 Celsius
•1935 C = 3515 F
———————————-
Converting Celsius to kelvin,We know that :
K = C + 273.15
C = K - 273.15
And from F to K=9/5(F+459.67)
And K to F =(9/5 *k)-459.67
•39.4 Celsius = 312.55 kelvin
•337 Fahrenheit = (337+ 459.67) × 5/9 =442.594 kelvin
1 mol of CO2 is 44.01g/mol
So multiply that by 2 to get 2 mol of CO2, which is 88.02g
Answer:
Explanation:
mole of HCl remaining after reaction with CaCO₃
= .3 M of NaOH of 32.47 mL
= .3 x .03247 moles
= .009741 moles
Initial HCl taken = .3 x .005 moles = .0015 moles
Moles of HCl reacted with CaCO₃
= .009741 - .0015 = .008241 moles
CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O .
1 mole 2 moles
2 moles of HCl reacts with 1 mole of CaCO₃
.008241 moles of HCl reacts with .5 x .008241 moles of CaCO₃
CaCO₃ reacted with HCl = .5 x .008241 = .00412 moles
the mass (in grams) of calcium carbonate in the tablet
= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )
