1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AfilCa [17]
2 years ago
5

Polyester and Nylon are examples of synthetic materials called polymers. A. True B. False

Chemistry
2 answers:
Rainbow [258]2 years ago
7 0

Answer:

The answer is true

Alik [6]2 years ago
5 0

Answer:

true is correct

You might be interested in
Question
AveGali [126]
A plateau is a flat, elevated landform that rises sharply above the surrounding area on at least one side. Plateaus occur on every continent and take up a third of the Earths land. They are one of the four major landforms, along with mountains, plains, and hills.
7 0
3 years ago
Read 2 more answers
Hello, I study Home MS Physical Science B-IC. Are there quizlets I can look up for the cumulative exam I have to take today?
Ludmilka [50]
Yes if you search up your subject or topic then put quizlet you’ll find your answer but you may need to login in to get the best experience of studying that you want
8 0
3 years ago
The change in its axis or orbit
saw5 [17]
Axis I hope this helped answer orbit or axis
6 0
2 years ago
Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?
blagie [28]
<h2>Answer:</h2>

She should notify her teacher.

<h2>Explanation:</h2>

Sodium Hydroxide is very corrosive in nature and it causes Redness, Pain, Serious skin burns and Blisters. Sodium hydroxide does not produce systemic toxicity, but is very CORROSIVE and can cause severe burns in all tissues that it comes in contact with. Therefore she should not touch it and she must notify her teacher as soon as possible.

4 0
2 years ago
(a) What is the total volume (in L) of gaseous products, measured at 350°C and 735 torr, when an automobile engine burns 100. g
Anarel [89]

Answer:

Part A

 The volume of the gaseous product  is  V = 787L

Part B

The volume of the the engine’s gaseous exhaust is  V_e = 2178 \ L

Explanation:

Part A

From the question we are told that

    The temperature is  T = 350^oC = 350 +273 =623K

     The pressure is  P = 735 \ torr = \frac{735}{760} =  0.967\ atm

     The of  C_8 H_{18} = 100.0g

The chemical equation for this combustion is

               2 C_8 H_{18}_{(l)} + 25O_2_{(l)} ----> 16CO_2_{(g)} + 18 H_2 O_{(g)}

 The number of moles of  C_8 H_{18} that reacted is mathematically represented as

               n = \frac{mass \ of \  C_8H_{18}  }{Molar \  mass \ of  C_8H_{18} }

The molar mass of  C_8 H_{18} is constant value which is

                  M = 114.23 \ g/mole  

So          n = \frac{100  }{114.23} }

             n = 0.8754 \ moles

The gaseous product in the reaction is CO_2_{(g)} and water vapour

Now from the reaction

    2 moles of C_8 H_{18}  will react with 25 moles of O_2 to give (16 + 18) moles of CO_2_{(g)} and  H_2 O_{(g)}

So

    1 mole of C_8 H_{18} will  react with 12.5 moles of  O_2 to give 17 moles of CO_2_{(g)} and  H_2 O_{(g)}

This implies that

    0.8754 moles of C_8 H_{18} will react with (12.5 * 0.8754 ) moles of O_2 to give  (17 * 0.8754) of CO_2_{(g)} and  H_2 O_{(g)}

So the no of moles of gaseous product is

         N_g = 17 * 0.8754

         N_g = 14.88 \ moles

From the ideal gas law

       PV = N_gRT

making V the subject

        V = \frac{N_gRT}{P}

Where R is the gas constant with a value R = 0.08206 \  L\cdot atm /K \cdot mole

Substituting values

          V = \frac{14.88* 0.08206 *623}{0.967}

          V = 787L

Part B

From the reaction the number of moles of oxygen that reacted is

         N_o = 0.8754 * 12.5

         N_o = 10.94 \ moles

The volume is

      V_o  = \frac{10.94 * 0.08206 *623}{0.967}

      V_o  = 579 \ L

No this volume is the 21% oxygen that reacted the 79% of air that did not react are the engine gaseous exhaust and this can be mathematically evaluated as

         V_e = V_o * \frac{0.79}{0.21}

Substituting values

       V_e = 579 * \frac{0.79}{0.21}

       V_e = 2178 \ L

3 0
3 years ago
Other questions:
  • Plz help will give brainliest, 50 pts!!! use your knowledge of the law of conversation of mass to answer the following question:
    11·1 answer
  • Looking for the products in a single replacement formula for: MgI2 + Cl2
    6·1 answer
  • Please help I will give you the brainiest.
    14·2 answers
  • Where is lithium used in the body?
    9·2 answers
  • True or false adding a solute to a solvent will raise the freezing point of the solvent.
    11·1 answer
  • What is the density of a block with a mass of 36 g and a volume of 9 cm3?
    9·1 answer
  • If 4.0 mol aluminum and 7.0 mol hydrogen bromide react according to the following equation, how many moles of hydrogen are forme
    15·1 answer
  • HELP PLEASE Iodine is a _____.
    8·1 answer
  • Which of the following is the best explanation of why an ionic compound formula is a ratio of atoms
    14·1 answer
  • We can find ___________ inside the proton​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!