Answer:
(a)
(b) 5220 j
(c) 1740 watt
(d) 3446.66 watt
Explanation:
We have given mass m = 290 kg
Initial velocity u = 0 m/sec
Final velocity v = 6 m/sec
Time t = 3 sec
From first equation of motion
v = u+at
So
(a) We know that force is given by
F = ma
So force will be
(b) From second equation of motion we know that
We know that work done is given by
W = F s = 580×9 =5220 j
(c) Time is given as t = 3 sec
We know that power is given as
(d) Time t = 1.5 sec
So
A machine can alter an input force<span> by changing its (1) magnitude, or (2) direction. All</span>machines<span> are subject to energy conservation in that no </span>machine can<span> output more energy (do more work) than the energy put into it.</span>
Answer:
Which of the following best describes a property of water?
A. Having a narrow temperature range for a liquid state
B. Requiring a low amount of heat to change temperature
C. Having high surface tension
D. Being unable to dissolve many substances
Explanation:
c
Explanation:
Given parameters:
Jermaine runs exactly 2 laps around a 400m track
Start time = 3:02:00PM
End time = 3:04:45PM
Unknown:
Distance traveled = ?
Speed = ?
Displacement = ?
Velocity = ?
Solution:
To solve this problem, we need to find the distance and time first;
Distance = 2 x 400 = 800m
Time taken = 3:04:45PM - 3:02:00PM = 165s
Speed = = = 4.85m/s
The velocity of the body is 0m/s and so is the displacement.
This is because the starting and finishing position of the Jermaine is the same.
Explanation:
"Rank the magnitude of the torque the signs exert about the point at which the rod is attached to the side of the building."
Torque is the cross product of the radius vector and force vector.
τ = r × F
The magnitude of the torque is the force times the perpendicular distance. In other words, it is the force times distance times the sine of the angle between them.
τ = F r sin θ
Let's assume the length of each rod is L meters. In each case, the weight is a vertical force, so the perpendicular distance is the horizontal distance between the wall and the sign.
A) τ = (50 kg × 10 m/s²) (L sin 30° m)
τ = 250L Nm
B) τ = (100 kg × 10 m/s²) (L m)
τ = 1000L Nm
C) τ = (50 kg × 10 m/s²) (L sin 60° m)
τ ≈ 433L Nm
D) τ = (90 kg × 10 m/s²) (L m)
τ = 900L Nm
Ranked from greatest to least:
B > D > C > A