The launch speed of a horizontally launched projectile is 13.28 m/s.
<h3>
Time of motion of the projectile</h3>
The time of motion is calculated as follows;
t = √(2h / g)
where;
- h is height of the cliff
- g is acceleration due to gravity
t = √(2 x 19.3 / 9.8)
t = 1.98 s
<h3>Launch speed of the projectile</h3>
X = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
Learn more about horizontal speed here: brainly.com/question/24949996
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Answer:
θ = 4.092 °
Explanation:
Given that
Initial Angular speed ,ωi = 0.76 rad/s
Final angular speed ,ωf= 2.96 rad/s
The angular acceleration ,α = 1 rad/s²
We know that
ωf² = ωi ²+ 2 α θ
θ=Angle rotates
2.96² = 0.76²+ 2 x 1 x θ
Therefore the angle rotates by machine part will be 4.092 degrees.
θ = 4.092 °
The best and most correct answer among the choices provided by the question is the second choice. The effect of El Nino was that it gave extremely cold weather in Michigan. I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
it's b
Explanation:
it's b cause ik I'm not wrong at these I did this when I was a kid and never got it wrong so it's b and will be cause b is the right answer so b it is
