Question

A train consists of 50 cars, each of which has a mass 6.8

Answer 1

Answer:

Explanation:

Given

mass of each car $m=6.8\times 10^3 kg$

acceleration of train $a=8\times 10^{-2} m/s^2$

Force required to pull this system

$F=50\times ma$

For first car

$F-T{1-2}=ma$

$T_{1-2}=50ma-ma$

$T_{1-2}=49 ma$

for second car

$T_{1-2}-T_{2-3}=ma$

$T_{2-3}=49 ma-ma$

$T_{2-3}=48 ma$

this form a pattern of the form

$T_{n-(n+1)}=(50-n)ma$

for (a)30 th and 31 st car tension

$T_{30-31}=(50-30) ma$

$T_{30-31}=20\times 6.8\times 10^{3}\times 8\times 10^{-2}$

$T_{30-31}=10,880\ N$

For 49 th and 50 th car

$T_{49-50}=(50-49) ma$

$T_{49-50}=544\ N$