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Mamont248 [21]
3 years ago
8

A train consists of 50 cars, each of which has a mass 6.8

Physics
1 answer:
kirill115 [55]3 years ago
6 0

Answer:

Explanation:

Given

mass of each car m=6.8\times 10^3 kg

acceleration of train a=8\times 10^{-2} m/s^2

Force required to pull this system

F=50\times ma

For first car

F-T{1-2}=ma

T_{1-2}=50ma-ma

T_{1-2}=49 ma

for second car

T_{1-2}-T_{2-3}=ma

T_{2-3}=49 ma-ma

T_{2-3}=48 ma

this form a pattern of the form

T_{n-(n+1)}=(50-n)ma

for (a)30 th and 31 st car tension

T_{30-31}=(50-30) ma

T_{30-31}=20\times 6.8\times 10^{3}\times 8\times 10^{-2}

T_{30-31}=10,880\ N

For 49 th and 50 th car

T_{49-50}=(50-49) ma

T_{49-50}=544\ N

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Answer:

a) 52.915 m

b) The vertical velocity is approximately 21.092 m/s

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Explanation:

a) The height of the window in the house from which the water was thrown = 15 m

The speed of the stream of water thrown = 20 m/s

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The acceleration due to gravity, g = 10 m/s²

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y = y₀ + u·t·sin(θ) + 1/2·g·t²

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The distance from the base of the house at which the water will fall = x ≈ 52.915 m

b) The velocity at which the water will reach the ground, 'v', is given as follows;

The vertical velocity, v_y = u·sin(θ)·t - g·t

At the ground, t ≈ 3.3128302 seconds

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The vertical velocity at which the water will reach the ground, v_y ≈ 21.092 m/s (downwards)

The resultant velocity, v = √(v_y² + vₓ²)

∴ v = √(21.092² + (0 × cos(37°))²) ≈ 26.5

The resultant velocity at which the water will reach the ground, v ≈ 26.5 m/s.

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The solutions to the question is the file attached to this explanation.

Lift,L= qC(l). S---------------------------(1).

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