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GrogVix [38]
3 years ago
10

How many moles of aluminum oxide are produced according to the reaction below given that you start with 10.0 g of Al and 19.0 gr

ams of O2? Reaction: 4Al + 3O2 → 2Al2O3 A) 0.396 B) 0.185 C) 0.741 D) 5.00 E) not enough information
Chemistry
1 answer:
Rasek [7]3 years ago
3 0

Answer:

The answer to your question is:   x = 0.185 mol of Al2O3

Explanation:

Data

10 g of Al and 19 grams of O2

Reaction:                                4Al       +       3O2       →       2Al2O3

                                            4(27)                3(32)               2 ( 102)

                                             108g                 96g                    204g

Limiting reactant

                                    108g  Al ------------------  96g  O2

                                      10 g      -----------------     x

                                     x = (10 x 96) / 108 = 8.9 g of O2

Then limiting reactant is Al

So

                                  108 g of Al ----------------------   204 g of Al2O3

                                    10 g         ----------------------     x

                                   x = (10 x 204) / 108 = 18.8 g of Al2O3

                                    102 g of Al2O3 ----------------- 1 mol

                                      18.8                 -----------------   x

                                  x = 0.185 mol of Al2O3

                         

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