It can be any row
Explanation:
An element with a valence electrons of 3 can be in any row on the periodic table.
The rows are the horizontal arrangement of elements on the periodic table.
Elements on the same row have the same energy level.
- The periodic table rows are called periods.
- It is only in the groups that we can find such element.
- Group 3 elements have 3 valence electrons.
- Since this group cuts through all the rows, therefore, elements with 3 valence electrons can be found in any row.
learn more:
Metalloids brainly.com/question/3023499
#learnwithBrainly
Answer:
0.64 m
Explanation:
Given that;
1L = 0.001 cubic metre
Then;
263 L = 263 L × 0.001 cubic metre/1L
= 0.263 cubic metre
Volume of a cube = l^3
l= 3√V
l= 3√0.263 cubic metre
l= 0.64 m
Explanation:
Exothermic reactions are those reactions in which heat is released.
Reactants→products+heat
For example, formation of ammonia from nitrogen and hydrogen is an exothermic reaction.
N2(g)+3H2(g)→2NH3(g)+92.2kJ
Endothermic reactions are those reactions in which heat is absorbed.
Reactants+heat→products
For example, dissociation of ammonia into nitrogen and hydrogen is an endothermic reaction.
2NH3 (g)+92.2kJ→
N2(g)+3H2(g)
Anything which changes the composition of starting material is a chemical property or chemical change. For example: you bake cake or cook food the heat changes composition of these. So cooking is a chemical change.
But evaporation of water is a physical change because even after evaporating it is still water molecules not changed to something else.
Combustion of any substance is burning of any substance in air. Combustion is actually the burning of a substance with oxygen in air. So, when a substance undergoes combustion it changes in it’s composition.
COMBUSTION IS A CHEMICAL CHANGE
Answer:
For example, 20mL of stock solution with 80mL of water.
Explanation:
60g of NaOH in 0,300L have a molar concentration of:
60g NaOH × ( 1 mol / 40g) = 1,5 moles of NaOH / 0,300L = 5M
If you want to mix this solution with water to produce a 1M NaOH solution you need to mix 1 part of volume of the stock solution per 5 parts of total volume. For example, mix 20mL of stock solution with 80mL of water. That is:
5M NaOH × ( 20mL stock solution / 20mL + 80mL -Total volume-) = 1M NaOH solution
I hope it helps!
