Answer:
Explanation:
Empirical formula of ionic compound formed by two ions 
and 
is 
(for 
) of AB (for x = y)
The above empirical formula is in accordance with charge neutrality principle
Here each cation (
and 
) can form two ionic compounds by combining with two given anions (
and 
).
So the four ionic compounds are:
Answer:
4.6305 * 10^-6 mol^3.L^-3
Explanation:
Firstly, we write the value for the solubility of Ca(IO3)2 in pure water. This equals 0.0105mol/L.
We proceed to write the dissociation reaction equation for Ca(IO3)2
Ca(IO3)2(s) <——->Ca2+(aq) + 2IO3-(aq)
We set up an ICE table to calculate the Ksp. ICE stands for initial, change and equilibrium. Let the concentration of the Ca(IO3)2 be x. We write the values for the ICE table as follows:
Ca2+(aq). 2IO3-(aq)
I. 0. 0.
C. +x. +2x
E. x. 2x
The solubility product Ksp = [Ca2+][IO3-]^2
Ksp = x * (2x)^2
Ksp = 4x^3
Recall, the solubility value for Ca(IO3)2 in pure water is 0.0105mol/L
We substitute this value for x
Ksp = 4(0.0105)^2 = 4 * 0.000001157625 = 4.6305 * 10^-6
Electrons and protons
Answer:A
The maximum number of moles of Nickel Carbonate (NiCO₃) that can form during a precipitation reaction is 0.025 mol. Hope this helped and have a great day!
