The molar volume of a gas at STP occupies <u>22.4 L.</u>
Option D
<u>Explanation:</u>
To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,
P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)
STP = 1 atm of pressure and 273 K for temperature
P = 1 atm
V = ?
n = 1 mole
R = 0.0821 atm L/mol K
T = 273 K
Using the equation,
By substituting the above values, in the equation,
V = 22.38 L
Answer:
Percent yield = 90.9%
Explanation:
Given data:
Mass of CaCO₃ = 50.0 g
Mass of CO₂ produced = 20.0 g
Percent yield = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaCO₃:
Number of moles = mass/molar mass
Number of moles = 50.0 g/ 100.1 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of CO₂ with CaCO₃.
CaCO₃ : CO₂
1 : 1
0.5 : 0.5
Mass of CO₂: Theoretical yield
Mass = number of moles × molar mass
Mass = 0.5 mol × 44 g/mol
Mass = 22 g
Percent yield:
Percent yield = ( actual yield / theoretical yield ) × 100
Percent yield = (20.0 g/ 22.0 g) × 100
Percent yield = 0.909 × 100
Percent yield = 90.9%
Answer:
Work done by the system = 4545 J
Explanation:
The expression for the calculation of work done is shown below as:
Where, P is the pressure
is the change in volume
From the question,
= 45 - 15 L = 30 L
P = 1.5 atm
Also, 1 atmL = 101 J
So,
(negative sign implies work is done by the system)
<u>Work done by the system = 4545 J</u>
Answer:
133.3atm
Explanation:
Given parameters:
Initial volume = 400ft³
Final volume = 3ft³
Initial pressure = 1atm
Unknown:
Final pressure = ?
Solution:
To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁V₁ = P₂V₂
P and V are pressure and volume
1 and 2 are initial and final states;
Insert parameters and solve;
1 x 400 = P₂ x 3
P₂ = 133.3atm
