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Darya [45]
3 years ago
12

In 2011, a computer named Watson competed against two humans on a popular television quiz show and won. Watson listened to each

question and responded.
1. What similarities and differences are there between a computer like Watson and the human nervous system?
Chemistry
1 answer:
Molodets [167]3 years ago
6 0

Answer:

A computer is made up of wires which is like nerves in our body they send signals throughout our bodies and tell us what to do about a situation. The hard drive of a computer is just like our brain which is the main component of the nervous system it controls involuntary, voluntary, movement and coordination. Also, just like the keys and mouse of a computer we have sensory neurons which pick up what is around us by touch.

Explanation:

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Part of the Appalachian mountain range is at the same latitude as Tokyo how would their climates compare
cricket20 [7]

Answer:

Explanation:

they compare because tokyo is closer to the equater and that means it would be a little warmer

8 0
3 years ago
How long is a grain of rice? Select the best estimate.
grigory [225]

Answer:

0.27 to 0.35 inch i found one that was 0.47 inches Lol

5 0
3 years ago
Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO
Irina-Kira [14]

Answer : The enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of H_2SO_4 will be,

S+H_2+2O_2\rightarrow H_2SO_4    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) S+O_2\rightarrow SO_2     \Delta H_1=-298.2

(2) SO_2+\frac{1}{2}O_2\rightarrow SO_3    \Delta H_2=-98.2

(3) SO_3+H_2O\rightarrow H_2SO_4    \Delta H_3=-130.2

(4) H_2+\frac{1}{2}O_2\rightarrow H_2O    \Delta H_4=-285.8

Now adding all the equations, we get the expression for enthalpy of formation of H_2SO_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)

\Delta H=-812.4kJ/mol

Therefore, the enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

3 0
3 years ago
PLZ HELP IM GIVING BRAINLEST TO WHOEVER HELPS ME AND GETS THE RIGHT ANSWER.
Nana76 [90]

Answer:

From hot tea to the ice cube

From the warm coffee to my cold hands

From the hot sand to my feet

Explanation:

Heat always travels from a hot object to a colder object, until equilibrium is reached and the objects are at the same temperature.

5 0
3 years ago
Read 2 more answers
How many bromine atoms are present in 39.0 g of ch2br2?
Mandarinka [93]
Answer is: there is  2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.
7 0
3 years ago
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