From the chemical equation given:
H2SO4+2KOH--->K2SO4+2H2O
the two reactants, H2SO4 and KOH, are in 1:2 stoichiometric ratio.
No. of moles of KOH = 2* no. of moles of H2SO4
=2*0.1*0.033
The concentration of KOH = no. of moles / volume
=2*0.1*0.033/0.05
=0.132M
Answer:
0.01185M = moles/0.02755L
0.02755*0.01185=0.00032647
Explanation:
Answer:
8)acids are electron pair acceptors and bases are electron pair donors
9)monoprotic
10)weak acids
The answer to that question is c
