The answer to the question is a
The reaction between HNO3 and Ba(OH)2 is given by the equation below;
2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2H2O
Moles of Barium hydroxide used;
= 0.200 × 0.039 l
= 0.0078 Moles
The mole ratio of HNO3 and Ba(OH)2 is 2: 1
Therefore; moles of nitric acid used will be;
= 0.0078 ×2 = 0.0156 moles
But; 0.0156 moles are equal to a volume of 0.10
The concentration of Nitric acid will be;
= (0.0156 × 1)/0.1
= 0.156 M
Answer:
1520mmHg
Explanation:
Data obtained from the question include:
V1 (initial volume) = 600 mL
P1 (initial pressure) = 760 mmHg
V2 (final volume) = 300 mL
P2 (final pressure) =.?
Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:
P1V1 = P2V2
760 x 600 = P2 x 300
Divide both side by 300
P2 = (760 x 600) /300
P2 = 1520mmHg
The final pressure of the gas is 1520mmHg
Answer:
Hydroxy(oxo)bismuthine oxide
