There are a couple of different approaches you can use for this. Here's one.
1. Determine how many digits repeat. (There is just one repeating digit.)
2. Call your number x. Multiply x by 10 to the power of the number of digits found in step 1.
3. Subtract the original number, then solve for x.
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If you recognize that 0.333... (repeating) is 1/3, then you know that 0.0333... (repeating) is 1/10×1/3 = 1/30. Add that to 0.8 = 4/5 and you get
... 4/5 + 1/30 = 24/30 + 1/30 = 25/30 = 5/6
15x+25y=975
x+y=55
Rearrange equation two so x is by itself.
x=-y+55
Plug the rearranged equation two into equation one.
15(-y+55)+25y=975
Evaluate the 'new' equation 1.
-15y+825+25y=975
10y+825=975
10y=150
y=15
Choose an equation to evaluate with y to get x. (i chose equation 2 because it was easier)
x+15=55
Evaluate the equation
x=55-15
x=40
So now we have x=40 and y=15
Evaluate those two terms with both equations to check the correctness.
15(40)+25(15)=975
600+375=975
975=975 (correct)
40+15=55
55=55 (correct)
Both equations are correct so the values of x and y are true.
Answer:
-x^4 - 2x^3 +2x + 5
Step-by-step explanation:
(x + 3) – [(x + 2) (xᶺ3 – 1)]
(x + 3) - [(x^4 - x + 2x^3 - 2)]
(x + 3) - (x^4 - x + 2x^3 - 2)
-x^4 - 2x^3 +2x + 5
Answer:
Outputs: {8, 9, 13, 23}
Step-by-step explanation:
Output is a fancy way of say y value. So the outputs of the data set are: {8, 9, 13, 23}.