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AleksandrR [38]
3 years ago
8

The chemical equation shows the production of magnesium chloride.

Chemistry
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

1 gram of H2 will be produced from 12 grams of Mg.

Explanation:

According to Stoichiometry, 0.5 moles of Mg are present. 1 mole of Mg produces 1 mole of H2, so 0.5 moles of Mg will produce 0.5 moles of H2. Multiplying molar mass of H2 i.e. 2 gram/mole with 0.5 moles, we can find the mass of H2 in grams which is 1 gram.

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Select the correct answer. Which of these elements is a transition metal?
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I don't see the options for an answer, so here is a list of all of the transition metals lol

  • <em>Scandium</em>
  • <em>Titanium</em>
  • <em>Vanadium</em>
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  • <em>Manganese</em>
  • <em>Iron</em>
  • <em>Cobalt</em>
  • <em>Nickel</em>
  • <em>Copper</em>
  • <em>Zinc</em>
  • <em>Yttrium</em>
  • <em>Zirconium</em>
  • <em>Niobium</em>
  • <em>Molybdenum</em>
  • <em>Technetium</em>
  • <em>Ruthenium</em>
  • <em>Rhodium</em>
  • <em>Palladium</em>
  • <em>Silver</em>
  • <em>Cadmium</em>
  • <em>Lanthanum</em>
  • <em>Hafnium</em>
  • <em>Tantalum</em>
  • <em>Tungsten</em>
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  • <em>Osmium</em>
  • <em>Iridium</em>
  • <em>Platinum</em>
  • <em>Gold</em>
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  • <em>Dubnium</em>
  • <em>Seaborgium</em>
  • <em>Bohrium</em>
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2 years ago
Most chemical bonds are
Lilit [14]

Answer:

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3 years ago
Which of the following is NOT a benefit of<br> using renewable energy sources?
Afina-wow [57]

Answer:

D, They produce fossil fuels

Explanation:

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3 0
3 years ago
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What is a factor that is deliberately changed in an experiment
Brrunno [24]
A factor that is changed in an experiment is called the Independent Variable.
4 0
3 years ago
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and
tatyana61 [14]

<u>Answer:</u> The equilibrium concentration of PCl_5 is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

The expression for equilibrium constant is given as:

K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}

We are given:

K_c=0.042

[PCl_3]=0.18M

[Cl_2]=0.30M

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

0.042=\frac{0.18\times 0.30}{[PCl_5]}

[PCl_5]=1.285

Hence, the equilibrium concentration of PCl_5 is 1.285 M.

6 0
3 years ago
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