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3 years ago

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What kind of glass is the following Si, O, Na, B, Al no plastic, no visible change, will shatters to high impact? 1. Pyrex Glass

2. Laminated soda-lime glass, 3. Ordinary Soda-Lime Glass, 4. Heat-tempered soda-lime glass?

1 answer:

tatuchka [14]3 years ago

7 0

The kind of glass that is Si, O, Na, B, Al no plastic, no visible change, that will shatter to high impact is 1. Pyrex glass.

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5.4×10^3 × 1.2×10^7

Nadya [2.5K]

5.4*10^3 * 1.2*10^7.

5.4 * 1000 * 1.2 * 10000000

Multiply them = 64800000000

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3 years ago

Calculate molecules in 1dm^3 of oxygen

Archy [21]

Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²

<h3>Further explanation</h3>

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

1 dm³ of oxygen = 1 L Oxygen

mol Oxygen :

$\tt \dfrac{1}{22.4}=0.045`mol$

molecules of Oxygen :

n=mol=0.045

No = 6.02.10²³

$\tt N=n\times No\\\\N=0.045\times 6.02\times 10^{23}\\\\N=2.71\times 10^{22}$

5 0

3 years ago

Can someone help me please I can’t get this hi

vesna_86 [32]

Milk mixture and heterogeneous

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4 years ago

A monatomic ideal gas that is initially at 1.50 * 105 Pa and has a volume of 0.0800 m3 is compressed adiabatically to a volume o

lubasha [3.4K]

Answer:

300000Pa or 3×10^5 Pa

Explanation:

Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.

Using Boyle's law

P1V1 = P2V2

P1 is the initial pressure = 1.5×10^5Pa

V1 is the initial volume = 0.08m3

P2 is the final pressure (required)

V2 is the final volume = 0.04 m3

From the formula, P2 = P1V1/V2

P2 = 1.5×10^5 × 0.08 ÷ 0.04

= 300000Pa or 3×10^5 Pa.

8 0

3 years ago

A researcher was attempting to quantify the amount of dichlorodiphenyltrichloroethane (DDT) in spinach with gas chromatography u

devlian [24]

Answer:

0.0136mg DDT / g spinach

Explanation:

Quantification in chromatography by internal standard has as formula:

RF = Aanalyte×Cstd / Astd×Canalyte <em>(1)</em>

<em>Where RF is response factor, A is area and C is concentration</em>

Replacing with first experiment values:

RF = 5019×3.20mg/L / 8179×6.37mg/L

RF = 0.308

In the next experiment, final concentration of chloroform was:

11.45mg/L × (1.25mL / 25.00mL) = <em>0.5725mg/L</em>

From (1), it is possible to write:

Aanalyte×Cstd / Astd×RF = Canalyte

Replacing:

6821×0.5725mg/L / 14061×0.308 = Canalyte

Canalyte = <em>0.9017mg/L</em>

as the sample was made from 0.750mL of extract. Concentration of extract is:

0.9017mg/L × (25.00mL / 0.750mL) = 30.06mg/L. As the extract has a volume of 2.40mL:

30.06mg/L × 2.40x10⁻³L = <em>0.07213mg of DDT in the extract</em>

As the extract was made from 5.29g of spinach:

0.07213mg of DDT in the extract / 5.29g spinach = <em>0.0136mg DDT / g spinach</em>

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5 0

3 years ago