Answer:
There are 0.1 moles of solute in 250 mL of 0.4 M solution.
Explanation:
First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.
250
ml . 1L/1000 L . 0.4mol / 1L
Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.
Answer:
B pancreas, since the pancreas secretes insulin
Explanation:
Answer:
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Explanation:
Nitrogen dioxide is a chemical compound with the formula NO 2.It is one of several nitrogen oxides. NO 2 is an intermediate in the industrial synthesis of nitric acid, millions of tons of which are produced each year for use primarily in the production of fertilizers.At higher temperatures it is a reddish-brown gas.
Hope This Helped Bro: "AdamDaAssasin"
Density is mass by volume
1 mL of nitric acid solution has a mass of 1.36 g
therefore 1000 mL has a mass of 1360 g
the molarity of solution is 2.48 mol/L
1 L of solution has 2.48 mol
the mass of 2.48 mol of HNO₃ is - 2.48 mol x 63 g/mol = 156.24 g
this means that 156.24 g of the solution consists of nitric acid
therefore percentage by mass - mass of nitric acid / total mass x 100%
concentration as percentage by mass = 156.24 g / 1360 g x 100%
percentage = 11.5%
Answer:
5. The valence electrons of both fluorine and carbon are found at about the same distance from their respective nuclei but the greater positive charge of the fluorine nucleus attracts its valence electrons more strongly.
Explanation:
Both fluorine and carbon are located in the second period of the periodic table, it means that they have 2 shells, so the valence electrons are found at about the same distance from their respective nuclei.
But fluorine has a higher atomic number, 9, than the carbon, 6. The atomic number represents how many protons there are in the nucleus, then there are more protons (positive charge) at the fluorine nucleus, and because of that, the attraction force between the nucleus and the valence electron is stronger in fluorine.
If the force is stronger, it will be necessary more energy to break the bond, so it will be harder to remove an electron from fluorine than from carbon.
