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melisa1 [442]
3 years ago
8

molecules that resemble fats but contain phosphate functional groups are called: a. steroids. b. polypeptides. c. phospholipids.

d. nucleic acid.
Chemistry
2 answers:
Rom4ik [11]3 years ago
8 0
The answer is C. Phospholipids because Lipids mean "Fat"
Rasek [7]3 years ago
3 0

Answer:

Phospholipids. (Ans. C)

Explanation:

Phospholipids are known as lipid molecules which containing waxes, fats, and some vitamins. Each molecule of phospholipid is made up of a phosphate group head, two fatty acids tails and a glycerol molecule. Phospholipid is main component of the cell membrane.

Fatty acid tails are made up of carbon and hydrogen where phosphate group head is made up of phosphorus molecule attached with four oxygen molecules. Glycerol is helping them to attached with each other.

Some function of phospholipids are:

1) Phospholipid is selectively permeable means semipermeable in nature.

2) Molecules which are dissolved in water can not pass through the membrane and molecules which are dissolved in fat can pass through the membrane.

3) Oxygen, urea, carbon dioxide and some molecules can easily pass through the cell membrane.

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Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74
Leona [35]

Answer:

D

Explanation:

The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.

Q = mc∆T

Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)

∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)

From the data provided in the question, we can deduce that:

Q = 16.7KJ = 16,700J

m = 225g

c = 1.74J/g.k

For the temperature, let the final temperature be f. This means our ∆T = f - 20

16,700 = 225 * 1.74 * (f - 20)

16700 = 391.5 (f - 20)

f - 20 = 16700/391.5

f - 20 = 42.7

f = 20 + 42.7 = 62.7

5 0
3 years ago
Lithium diisopropylamide (LDA) is used as a strong base in organic synthesis. LDA is itself prepared by an acid-base reaction be
kakasveta [241]

Explanation:

Lithium diisopropylamide (LDA) is used in many organic synthesis and is a strong base. It is prepared by the acid base reaction of N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) and butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ).

The equation is show below as:

[(CH₃)₂CH]₂NH + Li⁺⁻CH₂CH₂CH₂CH₃  ⇒  [(CH₃)₂CH]₂N⁻Li⁺  + CH₃CH₂CH₂CH₃

N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) is a weaker acid and hence,  LDA ( [(CH₃)₂CH]₂N⁻Li⁺ ) is stronger base. (Weaker acid has stronger conjugate base)

Butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ) is a very strong base and hence, butane ( CH₃CH₂CH₂CH₃ ) is a very weak acid. (Strong base has weaker conjugate acid)

5 0
3 years ago
Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. If 2.59 g of water is produc
max2010maxim [7]

<u>Answer:</u> The percent yield of the water is 31.98 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For methane:</u>

Given mass of methane = 6.58 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{6.58g}{16g/mol}=0.411mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 14.4 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{14.4g}{32g/mol}=0.45mol

The chemical equation for the combustion of methane is:

CH_4+2O_2\rightarrow CO_2+2H_2O

By Stoichiometry of the reaction:

2 moles of oxygen gas reacts with 1 mole of methane

So, 0.45 moles of oxygen gas will react with = \frac{1}{2}\times 0.45=0.225mol of methane

As, given amount of methane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction

2 moles of oxygen gas produces 2 moles of water

So, 0.45 moles of oxygen gas will produce = \frac{2}{2}\times 0.45=0.45 moles of water

  • Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 0.45 moles

Putting values in equation 1, we get:

0.45mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.45mol\times 18g/mol)=8.1g

  • To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 2.59 g

Theoretical yield of water = 8.1 g

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{2.59g}{8.1g}\times 100\\\\\% \text{yield of water}=31.98\%

Hence, the percent yield of the water is 31.98 %

4 0
3 years ago
Please help me with this question!<br> question number 2 only! PLEASE!!!
jeka57 [31]

Answer:

I'm not completely sure but possibly (HCO³)

6 0
4 years ago
When the alcohol thermometer is placed in 20∘c water, what temperature will the thermometer record?
Svet_ta [14]
The thermometer operates under the concept of the Zeroth Law of Thermodynamics. The thermometer displays the temperature of its surroundings, regardless of the identity of the substance. So, if the water is 20°C, then the thermometer displays 20°C.
5 0
4 years ago
Read 2 more answers
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