Answer:
Hence volume of oxygen gas measured at 0oC and 1atm, ineeded to burn completely 1L of propane gas (C3H8) under the same conditions is 5L.
Explanation:
hope it will help you
Explanation:
first one, a. lithium. it's the largest
Answer:
3.56L will be the obtained volume
Explanation:
0.3 M → Molarity
These are the moles of solute (for this case, the solute is KOH) that are contianed in 1L of solution
We dissolved 60 g of solute, so let's determine the moles:
60 g . 1 mol/ 56.1 g = 1.07 moles
Molarity(mol/L) = Mol / Volume(L)
Let's replace data: 0.3M = 1.07 mol / Volume(L)
0.3 mol/L = 1.07 mol / volume
Volume = 1.07 mol / 0.3mol/L = 3.56 L
H has a charge of +1, and O has a charge of -2. In this case, C in C7H12 would have a charge of -12/7 to balance it out. Meanwhile, C in CO2 would have a charge of +4. Since the charge of C went from negative to positive, this implies that C lost electrons, which is indicative of oxidation (and thus it was the reducing agent). Therefore, C7H12 was the reducing agent, while O2 was the oxidizing agent.