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3 years ago

Find the perimeter of the

Mathematics

1 answer:

seraphim [82]3 years ago

3 0

Answer:

$\huge \boxed{ \boxed{ \sf parimeter = 150cm}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

similarity
PEMDAS
equation

<h3>tips and formulas:</h3>

when two shapes are similar the rotio of two sides or area or parimeter is equal

<h3>let's solve:</h3>

$step - 1 : define$

let the parimeter of second shape be x

$\sf \frac{48}{60} = \frac{120}{x}$

$step - 2 : solve$

$\sf cross \: multiplication : \\ \sf 48x =72 00$
$\sf divide \: both \: sides \: by \: 48 : \\ \sf \frac{48x}{48} = \frac{7200}{48} \\ \therefore x = 150$

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The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure

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Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cylinder volume)

$V = \pi *r^2*h$

$V = 3.14 *2.5^2*7$

$V = 3.14*6.25*7$

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Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$