Let x represent the larger number.
Let y represent the smaller number.
x-y=4 Given
3x=5y-2 Given
Now we can just substitute; let x=4+y
Substitute 4+y for x in the second equation:
3(4+y)=5y-2
12+3y=5y-2
-2y=-14
y=7
Substitute back (into BOTH equations to double check work).
x, the larger number, is 11
,no.4, is the number line to shows the value of (X)
Answer:
Recall from Logarithm law Log a - Log b = Log (a/b)
so, Log 2 - Log 4 = Log ( 2/4)
= Log ( 1/2).
Also from the law
Log (a/b) = Log a - Log b
i.e Log (1/2) = Log 1 - Log 2
Recall: Log 1 = 0
which implies : Log 1 - Log 2 = 0 - Log 2
= - Log 2
Step-by-step explanation:
Answer:
Jon is 11 years old
Step-by-step explanation:
We write the following equations describing the sentences of the problem, using the letter M to represent Jon's mom's current age, and j to represent his current age.
First sentence: "<em>Six years ago Jon was one-sixth the age of his mother</em>."
translates into:
J - 6 = (M - 6) / 6
Second sentence: "<em>in four years time his age doubled and increased
</em>
<em>by 10 will match his mother's age</em>."
2 * (J + 4) + 10 = M + 4 which removing parentheses gives: 2 J + 18 = M + 4
We solve for "M" in the first equation
6 (J - 6) = M - 6
6 J - 36 = M - 6
M = 6 J - 30
and now use this result to substitute for M in the second equation
2 J + 18 = (6 J - 30) + 4
and work on solving for J
2 J + 18 = 6 J - 30 + 4
18 + 26 = 6 J - 2 J
44 = 4 J
J = 44 / 4
J = 11
Answer:
I think they will because both are being paid 8.50 each hour. But they are paid an extra couple dollars for starting right away. So they will have the same amount of money. If they work the same amount of hours but, Jose has to work a little bit longer.
Step-by-step explanation:
