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Alina [70]
3 years ago
10

Rachel worked 2.5 hours on Monday, 3.5 hours on Tuesday, 2 hours on Thursday, and 5 hours on Saturday. She is paid $10.66 per ho

ur. How much money did Rachel earn that week?
Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

$138.58

Step-by-step explanation:

You would first set up an equation. You want to know how much money Rachel earned that week, so let's refer to that by using variable t for total money earned this week.

Next, we also know that Rachel is paid 10.66 per hour, so we'll be multiplying it by the number of hours she worked this week. This allows us to set our equation up as follows:

10.66(2.5+3.5+2+5) = t

You would now add like terms.

10.66(13) = t

You would now multiply 10.66 and 13(total number of hours worked this week).

This would get us 138.58, or the total numnber of money Rachel earned this week.

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jace and chris sell their old toyd at a yard sale. they get $45.00. yhey agree that jace will have 2/5 of the money and chris wi
valentinak56 [21]

Answer:

Jace gets $18.00 while Chris keeps $27.00

Step-by-step explanation:

Jace

2/5 of $45.00

2/5 × 45

= $18.00

Jace gets $18.00

Chris:

$45.00 - $18.00 = $27.00

4 0
3 years ago
Which is a factor of the polynomial f(x) = 6x4 – 21x3 – 4x2 + 24x – 35?
QveST [7]
<span>I note that this problem starts out with "Which is a factor of ... "  This implies that you were given several answer choices.  If that's the case, it's unfortunate that you haven't shared them.

I thought I'd try finding roots of this function using synthetic division.  See below:

f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation.  Thanks.

Possible zeros of this poly are factors of 35:  plus or minus 1, plus or minus 5, plus or minus 7.  Use synthetic division; determine whether or not there is a non-zero remainder in each case.  If none of these work, form rational divisors from 35 and 6 and try them:  5/6, 7/6, 1/6, etc.

Provided that you have copied down the function 
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35  properly, this approach will eventually turn up 1 or 2 zeros of this poly.  Obviously it'd be much easier if you'd check out the possible answers given you with this problem.

By graphing this function, I found that the graph crosses the x-axis at 7/2.  There is another root.

Using synth. div. to check whether or not 7/2 is a root:

         ___________________________
7/2   /   6    -21    -4    24    -35
                   21      0   -14     35           
        ----------- ------------------------------
           6        0     -4    10       0

Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial.  Thus, (x-3.5), or (x-7/2), is a factor.

7 0
3 years ago
Read 2 more answers
a map has a scale of 2in: 6mi. if a two twons on a map is 10 in apart then how far apart are the real twons
Brilliant_brown [7]

Answer:  30 miles

Work Shown:

2 in : 6 mi

5*2 in : 5*6 mi

10 in : 30 mi

7 0
2 years ago
Given that M is the midpoint of L and P. If LP=4x-1, LM=8, find x and LP
Alenkinab [10]

Answer:

LP = 16 units (8 + 8)

x = 4.25 units

Step-by-step explanation:

8 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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