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rusak2 [61]
4 years ago
5

Predict which of the following would shift the equilibrium to the right in the following reaction. C2H2 + H2O Two arrows stacked

on top of each other. The top arrow points to the right. The bottom arrow points to the left. CH3CHO removing H2O (g) from the system adding CH3CHO (g) to the system removing C2H2 (g) from the system adding H2O (g) to the system
Chemistry
2 answers:
vlada-n [284]4 years ago
7 0
Chemical reaction

C2H2(g) + H2O(g) ⇄ CH2CHO(g)

a) Removing H2O(g) from the system

Remember that Le Chatelier principle states that when an equilibrium is disturbed the system will try to counteract to restate the equilibrim.

If you remove H2O(g) then the equilibrium will be displaced to the left, trying to produce more H2O(g), which means to reduce CH3CHO(g) and increasing the C2H2(g).

b) Adding CH3CHO(g)

To counteract the addition of CH3CHO(g) the system will try to regain equilibrium by producing more reactants: C2H2(g) and H2O(g)

c) Removing C2H2(g)

The system will again displace to the left, that is CH3CHO(g) will reduce and H2O(g) will increase.

d) Adding H2O(g)

The systmen will displace to the right reducing C2H2(g) and increasing CH3CHO(g).


deff fn [24]4 years ago
7 0

Answer:

Adding H2O to the system.

(Got this right on my test!)

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Convert 5.28 x 1019 molecules of C6H1206 to grams.
nlexa [21]

Answer:

m=0.0158g

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g

Best regards!

5 0
3 years ago
An experiment shows that a 250 −mL gas sample has a mass of 0.436 g at a pressure of 742 mmHg and a temperature of 27 ∘C.
icang [17]

Answer:

41.9 g/ mol hope that helps you out

Explanation:

d=p.m/ r.t

8 0
3 years ago
An analytical chemist is titrating of a solution of nitrous acid with a solution of . The of nitrous acid is . Calculate the pH
Burka [1]

Answer:

pH = 2.69

Explanation:

The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

<em />

The reaction of HNO₂ with KOH is:

HNO₂ + KOH → NO₂⁻ + H₂O + K⁺

Moles of HNO₂ and KOH that react are:

HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>

KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>

That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]

<h3>pH = 2.69</h3>
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