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rusak2 [61]
4 years ago
5

Predict which of the following would shift the equilibrium to the right in the following reaction. C2H2 + H2O Two arrows stacked

on top of each other. The top arrow points to the right. The bottom arrow points to the left. CH3CHO removing H2O (g) from the system adding CH3CHO (g) to the system removing C2H2 (g) from the system adding H2O (g) to the system
Chemistry
2 answers:
vlada-n [284]4 years ago
7 0
Chemical reaction

C2H2(g) + H2O(g) ⇄ CH2CHO(g)

a) Removing H2O(g) from the system

Remember that Le Chatelier principle states that when an equilibrium is disturbed the system will try to counteract to restate the equilibrim.

If you remove H2O(g) then the equilibrium will be displaced to the left, trying to produce more H2O(g), which means to reduce CH3CHO(g) and increasing the C2H2(g).

b) Adding CH3CHO(g)

To counteract the addition of CH3CHO(g) the system will try to regain equilibrium by producing more reactants: C2H2(g) and H2O(g)

c) Removing C2H2(g)

The system will again displace to the left, that is CH3CHO(g) will reduce and H2O(g) will increase.

d) Adding H2O(g)

The systmen will displace to the right reducing C2H2(g) and increasing CH3CHO(g).


deff fn [24]4 years ago
7 0

Answer:

Adding H2O to the system.

(Got this right on my test!)

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Electrons and newtrons is that what ur asking for
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2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Slav-nsk [51]

Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

<em>2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂</em>

<em />

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

<em></em>

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

<em>0.589 moles of AgC</em>l. In mass:

0.589 moles of AgCl × (143.32g / mol) =<em> 84.4g of AgCl</em>

3 0
4 years ago
In the example in the lesson, 0.10 mole of sodium chloride or magnesium chloride or aluminum chloride was added to one liter of
Sonja [21]
Answers:
1. 0.00010 mol/m
2. 0.00020 moles
4 0
3 years ago
Read 2 more answers
Which of the followings are true 1,3-BPG? A. It regulates Hb B. It contains a high-energy bond C. It contains two ester bonds D.
weeeeeb [17]

Answer:

D. It contains a phosphate with higher phosphoryl transfer potential than ATP

Explanation:

1,3-Bisphosphoglycerate contains a phosphate group that has high phosphoryl transfer potential than ATP (they can transfer the phosphoryl group to ATP). Other high phosphoryl transfer potential groups include :Creatine kinase and phosphoenolpyruvate.

7 0
3 years ago
How many grams of Chromium(III) nitrate are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate to produce chromiu
mina [271]

Grams of Chromium(III) nitrate produced : 268.95 g

<h3>Further explanation</h3>

Given

0.85 moles of Lead(IV) nitrate

Required

grams of Chromium(III) nitrate

Solution

Reaction

Balanced equation :

<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>

From the equation, mol ratio of Pb(NO₃)₄  : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃

mol Cr(NO₃)₃ =

\tt \dfrac{4}{3}\times 0.85=1.13

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :

mass = mol x MW

mass = 1.13 x 238.0108

mass = 268.95 g

7 0
3 years ago
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