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Answer:
a₂ = m₁ / m₂ a₁
Explanation:
For this exercise we note that the attraction between the two stars is an action and reaction force, therefore it has the same magnitude, but it is applied to each of the bodies
Let's apply Newton's second law on the star 1
F₁ = m₁ a₁
Newton's second law in star 2
F₂ = m₂ a₂
| F₁ | = | F₂ |
m₁ a₁ = m₂ a₂
a₂ = m₁ / m₂ a₁
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):

The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg

in eV you have:

The kinetic energy of the proton is 1.29eV
Answer:
a 15.22 m/s
b 45.65 m
Explanation:
Using the same formula,
x = vt, where
x is now 45.65, and
t is 3 s, then
45.65 = 3v
v = 45.65/3
v = 15.22 m/s
See the attachment for the part b. We used the distance gotten in part B, to find question A
Explanation:
The cross section per unit length is uniform, so ρ is constant.
The center of mass is therefore:
x_avg = (∫₀ᴸ x ρ dL) / (∫₀ᴸ ρ dL)
x_avg = (∫₀ᴸ x dL) / (∫₀ᴸ dL)
x_avg = (½ L²) / (L)
x_avg = ½ L