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ziro4ka [17]
3 years ago
14

What is bigger 95.58 or 95.850

Mathematics
2 answers:
natta225 [31]3 years ago
8 0

Answer:

95.850

95.850

95.58

eight is bigger than 5 so it is 95.850

Lisa [10]3 years ago
4 0

Answer:

i think 95.58 bc the bigger the decimal the smaller it is and 95.850 is bigger than 95.58 which means it's smaller. So yeah the answer is 95.58

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<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Ctext%7Bquestion%7D%7D%7D%20%3A%20" id="TexFormula1"
Inga [223]

Answer:

y=-\sqrt{3}x+2

Step-by-step explanation:

We want to find the equation of a straight line that cuts off an intercept of 2 from the y-axis, and whose perpendicular distance from the origin is 1.

We will let Point M be (x, y). As we know, Point R will be (0, 2) and Point O (the origin) will be (0, 0).

First, we can use the distance formula to determine values for M. The distance formula is given by:

\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Since we know that the distance between O and M is 1, d=1.

And we will let M(x, y) be (x₂, y₂) and O(0, 0) be (x₁, y₁). So:

\displaystyle 1=\sqrt{(x-0)^2+(y-0)^2}

Simplify:

1=\sqrt{x^2+y^2}

We can solve for y. Square both sides:

1=x^2+y^2

Rearranging gives:

y^2=1-x^2

Take the square root of both sides. Since M is in the first quadrant, we only need to worry about the positive case. Therefore:

y=\sqrt{1-x^2}

So, Point M is now given by (we substitute the above equation for y):

M(x,\sqrt{1-x^2})

We know that Segment OM is perpendicular to Line RM.

Therefore, their <em>slopes will be negative reciprocals</em> of each other.

So, let’s find the slope of each segment/line. We will use the slope formula given by:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Segment OM:

For OM, we have two points: O(0, 0) and M(x, √(1-x²)). So, the slope will be:

\displaystyle m_{OM}=\frac{\sqrt{1-x^2}-0}{x-0}=\frac{\sqrt{1-x^2}}{x}

Line RM:

For RM, we have the two points R(0, 2) and M(x, √(1-x²)). So, the slope will be:

\displaystyle m_{RM}=\frac{\sqrt{1-x^2}-2}{x-0}=\frac{\sqrt{1-x^2}-2}{x}

Since their slopes are negative reciprocals of each other, this means that:

m_{OM}=-(m_{RM})^{-1}

Substitute:

\displaystyle \frac{\sqrt{1-x^2}}{x}=-\Big(\frac{\sqrt{1-x^2}-2}{x}\Big)^{-1}

Now, we can solve for x. Simplify:

\displaystyle \frac{\sqrt{1-x^2}}{x}=\frac{x}{2-\sqrt{1-x^2}}

Cross-multiply:

x(x)=\sqrt{1-x^2}(2-\sqrt{1-x^2})

Distribute:

x^2=2\sqrt{1-x^2}-(\sqrt{1-x^2})^2

Simplify:

x^2=2\sqrt{1-x^2}-(1-x^2)

Distribute:

x^2=2\sqrt{1-x^2}-1+x^2

So:

0=2\sqrt{1-x^2}-1

Adding 1 and then dividing by 2 yields:

\displaystyle \frac{1}{2}=\sqrt{1-x^2}

Then:

\displaystyle \frac{1}{4}=1-x^2

Therefore, the value of x is:

\displaystyle \begin{aligned}\frac{1}{4}-1&=-x^2\\-\frac{3}{4}&=-x^2\\ \frac{3}{4}&=x^2\\ \frac{\sqrt{3}}{2}&=x\end{aligned}

Then, Point M will be:

\begin{aligned} \displaystyle M(x,\sqrt{1-x^2})&=M(\frac{\sqrt{3}}{2}, \sqrt{1-\Big(\frac{\sqrt{3}}{2}\Big)^2)}\\M&=(\frac{\sqrt3}{2},\frac{1}{2})\end{aligned}

Therefore, the slope of Line RM will be:

\displaystyle \begin{aligned}m_{RM}&=\frac{\frac{1}{2}-2}{\frac{\sqrt{3}}{2}-0} \\ &=\frac{\frac{-3}{2}}{\frac{\sqrt{3}}{2}}\\&=-\frac{3}{\sqrt3}\\&=-\sqrt3\end{aligned}

And since we know that R is (0, 2), R is the y-intercept of RM. Then, using the slope-intercept form:

y=mx+b

We can see that the equation of Line RM is:

y=-\sqrt{3}x+2

6 0
3 years ago
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Item 2 In a box-and-whisker plot, what fraction of the data is greater than the first quartile? Enter the fraction in simplified
Serga [27]

Answer:

3/4= 75 % of the data is greater than the first quartile in a box-and-whisker plot.

Step-by-step explanation:

75 % of the data is greater than the first quartile in a box-and-whisker plot.

The first quartile denoted by Q1 is the median of the lower half of the data set.

This means that 25% of the values lie in the first quartile and 75 % of the values lie above the first quartile.

In the box and whisker plot  the longer box indicates the interquartile range whereas the sides represent the 1st and 3rd quartile. The first quartile is the region where the values start and increase to the interquartile range.

75 % means = 75/100 or 0.75 or 3/4

75/100= 15/20= 3/4

6 0
3 years ago
G(x) = x2 + 3x - 2, find g(-2) Please Explain
Vlad1618 [11]
G(-2) means "evaluate the equation at -2"; it's asking you to swap out the "x" in the equation and sub in -2.

g(x) = x² + 3x - 2  ... plug in -2
g(-2) = (-2)² + 3(-2) - 2  ... simplify
g(-2) = 4 + (-6) - 2 ... add/subtract
g(-2) = -4
5 0
3 years ago
What is the angle that forms from the two vectors below? *<br> v= &lt;-12,5&gt;, w= &lt;3,-10&gt;
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

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2 years ago
There are 48 students in the 6th-grade band. If this represents 30% of the students in 6th grade, how many students are in the 6
Artemon [7]

Answer:

160

Step-by-step explanation:

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4 0
2 years ago
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