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yaroslaw [1]
3 years ago
13

Which Lewis electron-dot diagram represents an atom of a Group 13 element in the ground state?

Chemistry
1 answer:
inessss [21]3 years ago
6 0

Answer:

sodium chloride and lead (II) acetate

potassium sulfate and strontium iodide

chromium (III) nitrate and sodium phosphate

1.       2NaCl + Pb(CH3COO)2 → 2NaCH3COO + PbCl2

2.       K2SO4 + SrI2 → KI + SrSO4

3.       Cr(NO3)3 + Na3PO4 →CrPO4 + NaNO3

Explanation:

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A sample that contains only SrCO3 and BaCO3 weighs 0.846 g. When it is dissolved in excess acid, 0.234 g carbon dioxide is liber
In-s [12.5K]

Answer:28.605

Explanation:First, the molar mass of of SrCO3, BaCO3 and CO2 has to be calculated, (using the molar mass of each element Sr = 87.62, Ba = 137.327, C=12.011, O= 16.00)

The molar masses are;

SrCO3 = 87.62 + 12.011 + (3*16) = 147.631g/mol

BaCO3 = 79.904 + 12.011 + (3*16) = 197.34 g/mol

CO2 = 12.011 + (2*16) = 44.011 g/mol

To obtain one of the equations to solve the problem;

The sample is made of SrCO3 and BaCO3 and has a mass of 0.846 g. Representing the mass of SrCO3 as ma and that of BaCO3 as mb. The first equation can be written as:

ma + mb = 0.846g                 (1)

To obtain another equation in order to be able to determine the different percentages of the compounds (SrCO3 and BaCO3) that make of the sample, a relationship can be obtained by determining the relationship between the number of moles of CO2 formed as the mass of the SrCO3 and BaCO3;

The number of moles of CO2 formed = (mass of CO2)/(molar mass) =0.234/44.011 =0.00532moles

CO2 contains 1 mole of carbon (C) so therefore 0.00532 moles of CO2 contains 0.00532 moles of C

The sample produced 0.00532 moles of CO2, therefore the number of moles SrCO3 and BaCO3 that produced this amount can be calculated using the formula;

= (mass )/(molar mass)

No of moles of SrCO3 and BaCO3 will be ma/147.631 and mb/197.34 moles respectively

The total amount of C molecules produced by SrCO3 and BaCO3 will be 0.00532 moles of C

The second equation can be written as

ma/147.631 + mb/197.34= 0.00532          (2)

Solving Equation (1) and (2) simultaneously;

ma = 0.604g; mb = 0.242g

Therefore the percentage of BaCO3   = (mass of BaCO3 )/(mass of sample )*100

                                                         = 0.242/(0.846 )*100

                                                         = 28.605%

5 0
3 years ago
What happens after sound waves create vibrations in the ear?​
otez555 [7]

Explanation:

3 little bones in ear takes that vibration and empowers them. Then they transfer the vibrations to next part of ear.

7 0
3 years ago
Which of the following is a disadvantage of genetic engineering?
Solnce55 [7]

Answer:

A disadvantage is pharmaceuticals

Explanation:

4 0
3 years ago
Write the balanced nuclear equation for the following. (Use the lowest possible coefficients. Omit states-of-matter in your answ
olga55 [171]

Answer:

_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}

Explanation:

The unbalanced nuclear equation is

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow ?

It is convenient to replace the question by an atomic symbol, _{x}^{y}\text{Z}, where <em>x </em>= the atomic number, <em>y</em> = the mass number, and Z = the symbol of the element.

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}

Then your equation becomes

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}

The main point to remember in balancing nuclear equations is that the <em>sums of the superscripts and of the subscripts</em> must be the same on each side of the equation.  

Then

93 – 1 = <em>x</em>, so <em>x</em> = 92

232 + 0 = <em>y</em>, so <em>y</em> = 232

Element 92 is uranium, so the nuclear equation becomes

_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}

3 0
3 years ago
How many liters of 0.85 M HCl solution would react completely with 3.5 moles Ca(OH)2?
True [87]
The reaction of Ca(oH)2 with HCl produces calcium chloride (CaCl2) and water (H2O). The stiochiometric equation is 2HCl + Ca(OH)2 = CaCl2 + 2H2O. In this case, 2 moles of HCl stoichiometrically reacts with one mole of calcium hydroxide. Hence for 3.5 moles of Ca(OH)2, there should be 1.75 moles of HCl needed. Given 0.85 M HCl, to get the volume, we divide 1.75 moles by 0.85 M. The volume needed is 2.0588 liters.
5 0
3 years ago
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