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yaroslaw [1]
3 years ago
13

Which Lewis electron-dot diagram represents an atom of a Group 13 element in the ground state?

Chemistry
1 answer:
inessss [21]3 years ago
6 0

Answer:

sodium chloride and lead (II) acetate

potassium sulfate and strontium iodide

chromium (III) nitrate and sodium phosphate

1.       2NaCl + Pb(CH3COO)2 → 2NaCH3COO + PbCl2

2.       K2SO4 + SrI2 → KI + SrSO4

3.       Cr(NO3)3 + Na3PO4 →CrPO4 + NaNO3

Explanation:

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DanielleElmas [232]
I want to say 8 but i'm not sure. I just did a lesson on this and my notes say it could be 8 but then again I'm not sure. 
5 0
3 years ago
From these two reactions at 298 K, V2O3(s) + 3CO(g) → 2V(s) + 3CO2(g); ΔH° = 369.8 kJ; ΔS° = 8.3 J/K V2O5(s) + 2CO(g) → V2O3(s)
gregori [183]

Answer:

ΔG° = -133,1 kJ

Explanation:

For the reactions:

<em>(1) </em>V₂O₃(s) + 3CO(g) → 2V(s) + 3CO₂(g); ΔH° = 369,8 kJ; ΔS° = 8,3 J/K

<em>(2) </em>V₂O₅(s) + 2CO(g) → V₂O₃(s) + 2CO₂(g); ΔH° = –234,2 kJ; ΔS° = 0,2 J/K

By Hess's law it is possible to obtain the ΔH° and ΔS° of:

2V(s) + 5CO₂(g) → V₂O₅(s) + 5CO(g)

Substracting -(1)-(2), that means:

ΔH° = -369,8 kJ - (-234,2 kJ) = <em>-135,6 kJ</em>

ΔS° = - 8,3 J/K - 0,2 J/K =<em> -8,5 J/K</em>

Using: ΔG° = ΔH° - TΔS° at 298K

ΔG° = -135,6 kJ - 298K×-8,5x10⁻³kJ/K

<em>ΔG° = -133,1 kJ</em>

I hope it helps!

7 0
3 years ago
How are the formulas and names of ionic compounds written
MA_775_DIABLO [31]
Put the cation (a positive ion, the metal in this case,) without changing anything, then the nonmetal, or anion. For the nonmetal, change the ending to -ide. For example, if you have potassium and chlorine, you would have potassium chloride. Hope this helps!
3 0
3 years ago
How do you balance Sb+I2=SbI3 show work please
egoroff_w [7]

Answer:

 2Sb   +    3I₂    →    2SbI₃

Explanation:

The reaction expression we need to balance is:

         Sb   +    I₂    →    SbI₃

To balance this expression, we need to assign the variables a,b and c to each specie as the coefficient that will balance the expression.

              aSb   +    bI₂    →    cSbI₃

Conserving Sb :  a  = c

                      I :   2b  = 3c

let a  = 1, c  = 1,  b  = \frac{3}{2}  

   Multiply through by 2;

 a  = 2, b  = 3  and c  = 2

         2Sb   +    3I₂    →    2SbI₃

7 0
3 years ago
Certain antibacterial soap kill 99% of the bacteria present on heand. Constant use of these soaps could be harmful over time bec
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The soap stimulates skin cell division.

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