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Brilliant_brown [7]
3 years ago
12

Which of the following is an example of a heterogeneous mixture A.salt-water B.granite C.water(Na)

Chemistry
1 answer:
sladkih [1.3K]3 years ago
5 0
Hi!

B. Granite is an example of a heterogenous mixture.
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Firewood burns and ashes remain<br><br> is it a chemical or physical change?
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What’s the bladder wall made up of?
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Explanation:

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Which soup would likely be more flavorful, a nicely heated but not too hot to eat bowl of soup or a bowl of leftover soup direct
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HNO3 + S --&gt; H2SO4 + NO Now identify the element oxidized and the element reduced. Which element is oxidized? Which element i
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<u>Answer:</u> S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

<u>Explanation:</u>

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.

For the given chemical reaction:

HNO_3+S\rightarrow H_2SO_4+NO

<u>On the reactant side:</u>

Oxidation number of H = +1

Oxidation number of N = +5

Oxidation number of O = -2

Oxidation number of S = 0

<u>On the product side:</u>

Oxidation number of H = +1

Oxidation number of N = +2

Oxidation number of O = -2

Oxidation number of S = +6

As the oxidation number of S is increasing from 0 to +6. Thus, it is getting oxidized. Similarly, the oxidation number of N is decreasing from +5 to +2. Thus, it is getting reduced.

The oxidation numbers of O and H remain the same on both sides of the reaction. Thus, they are neither getting oxidized or reduced.

Hence, S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

3 0
3 years ago
A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L. If the containe
Morgarella [4.7K]

Answer:

The pressure inside the container is 6.7 atm

Explanation:

We have the ideal gas equation: P x V = n x R x T

whereas, P (pressure, atm), V (volume, L), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)

Since the container is evacuated and then sealed, the volume of the body of gas is the volume of the container.

So we can calculate the pressure by

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where as,

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Hence P = 0.934 x 0.082 x 298 / 3.4 L = 6.7 atm

3 0
3 years ago
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