It would be equal to 110 2/7
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Answer:
Step-by-step explanation:
We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).
p = 12/100 = 0.12
number of success, x = 20
n = 200
the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)
From the binomial probability calculator,
P(x ≥ 20) = 0.84
Answer:
![\sqrt[3]{5x+10}=5 / ^{3}\\ 5x+10=125\\5x=115/:5\\x=23](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%2B10%7D%3D5%20%2F%20%5E%7B3%7D%5C%5C%20%205x%2B10%3D125%5C%5C5x%3D115%2F%3A5%5C%5Cx%3D23)
If you mean that :
this is
![\sqrt[3]{5x}+10=5 /^{3} \\5x+1000=125\\5x=-875/:5\\x=-175](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%2B10%3D5%20%2F%5E%7B3%7D%20%5C%5C5x%2B1000%3D125%5C%5C5x%3D-875%2F%3A5%5C%5Cx%3D-175)
Step-by-step explanation:
Answer:
3.7*10⁷ people.
Step-by-step explanation:
Estimated population of California = 3.9*10⁷ people
Estimated population of Maine = 1.3*10⁶ people.
Let x represent the estimated number of people that live in California more than Maine.
The number of people that live in California more than Maine can be found by finding the difference between the population of California to Maine.
No. Of people living in California - no. Of people living in Maine = estimated no of people that live in California more than Maine.
X = 3.9*10⁷ - 1.3*10⁶
X = 3.7*10⁷ people
About 3.7*10⁷ people live more in California than Maine