A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?

Chemistry

1 answer:

Komok [63]2 years ago

7 0

Answer:

Ok:

Explanation:

So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.

You might be interested in

How a cation is formed by an atom?

fenix001 [56]

Answer:

Cations are positively charged atoms and hence we need to make the atom positively charged in order to get a cation

We know that an atom is neutral as a whole, so we have equal number of electrons and protons

since we cannot mess with the number of protons in an atom, we have to do it by altering the number of electrons

If we reduce the amount of electrons in an atom, the net charge will be positive and hence a cation will be formed

4 0

3 years ago

Explain electronegativity and how it relates to both molecular and ionic bonding.

Keith_Richards [23]

Answer:

Mama Mo Blue Tun Po

<h2>Explanation:</h2><h2>HOPE THIS HELPS PO :D</h2>

3 0

2 years ago

If 1.38×1022 atoms of element y have a mass of 1.50 g, what is the identity of y? express your answer as a chemical symbol.

zaharov [31]

1,38×10²² = 0,138×10²³

0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol

It's ZINC (Zn)

:•)

4 0

2 years ago

Read 2 more answers

How would you prepare 1.00 L of a 0.50 M solution of each of the following?

Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated 12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

$n_1=n_2$