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Alex17521 [72]
3 years ago
15

How many liters would you need to make a 0.8 M solution with 20 grams of lithium chloride?

Chemistry
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

0.5875L

Explanation:

concentration = mole/ volume

n(LiCl) = 20 / (7 + 35.5) = 0.47 mol

volume = mole / conc.

volume = 0.47 /0.8

= 0.5875 dm³ = 0.5875L

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Answer:

2H⁺ + 2MnO4⁻ + 3CN⁻ → 2MnO₂  + H₂O + 3CNO⁻

Explanation:

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In right side permangante, with Mn element has +7 as oxidation number.

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To ballance the half reactions, I have to multiply x2 (reduction) and x3 (oxidation)  so I can cancel, the electrons.

2H⁺  +  2MnO4⁻ + 3CN⁻ → 2MnO₂  + H₂O + 3CNO⁻

The electrons are now cancelled, and I can also modify water. In reactant side I have 3H₂O and in product side, I have 4H₂O so, H₂O in right side is gone so I finally obtained 1 H₂O on left. I had 8H⁺ on right, and 6H⁺ on left, so finally I obtained 2H⁺ on right, and the protons of product side are gone.

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Answer:

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