3 years ago

How many liters would you need to make a 0.8 M solution with 20 grams of lithium chloride?

Chemistry

1 answer:

worty [1.4K]3 years ago

5 0

Answer:

0.5875L

Explanation:

concentration = mole/ volume

n(LiCl) = 20 / (7 + 35.5) = 0.47 mol

volume = mole / conc.

volume = 0.47 /0.8

= 0.5875 dm³ = 0.5875L

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