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Dima020 [189]
3 years ago
15

If i add water to 100 mL of a 0.15M NaOH solution until the final volume 150mL , what will the molarity of the diluted solution

be ?
Chemistry
1 answer:
labwork [276]3 years ago
3 0
0,15 moles of NaOH-------in------------1000ml
x moles of NaOH------------in--------100ml
x = 0,015 moles of NaOH

final volume = 150ml

0,015 moles of NaOH---in-------150ml
x moles of NaOH--------------in-----1000ml
x = 0,1 moles of NaOH

answer:  0,1mol/dm³  (molarity)
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Soloha48 [4]

Answer:

The force increases because it is part of a Newton’s third law pair of forces with the force that the star exerts on the planet.

Explanation:

Force between two objects can be expressed by an equation:

F = G • m1 • m2 / r^2,

where m1 and m2 are objects' masses, r is the distance between them, and G is a gravitational constant.

That means that greater the masses or lesser the distance, the force will be greater, and vice versa.

This force exists between any two objects, but is generally extremely weak, so it's best observed with big and large objects with great mass, such as planets and stars.

This force, whatever its magnitude may be, always works on both objects, following the third Newton's law.

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3 0
3 years ago
Calculate how many moles of carbon dioxide are contained in 5.57 x 10²¹ molecules of CO₂
Alex777 [14]
<h2>Answer:  0.00925 mol </h2>

Explanation:

Moles = # of molecules ÷ Avogadro's Number  

         =  (5.57 × 10²¹ molecules) ÷ (6.022 × 10²³ molecules/mol)  

         =  0.00925 mol

<h3>∴ the 5.57 x 10²¹ molecules of carbon dioxide ≡ 0.00925 mol</h3>
3 0
2 years ago
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7 0
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How much energy is required to heat 40g of water from -7 degrees Celsius to 108 degrees Celsius (Lf= 335,000J/Kg for ice)
solniwko [45]
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     calculation

Q(heat)=  M( mass)  x c(specific heat capacity) xdelta t( change in temperature)

M=  40g=  40/1000= 0.04 Kg
C=  335,000 j/kg/c
delta T   (    108 --7= 115  c)

Q  is therefore   =  0.04 g x  335000 j/kg/c  x 115 c  = 1541,000  joules


6 0
3 years ago
The standard entropy change of a reaction has a positive value. This reaction results in: Select the correct answer below: a dec
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