NO2- +7H+ + 6e->> NH3 + 2H2O ( N goes from +3 to -3)
<span>Al + 2 H2O >> AlO2- + 4H+ + 3e- </span>
<span>NO2- + 2Al + 2H2O >> NH3 + 2AlO2- + H+ </span>
<span>add OH- on the left and on the right </span>
<span>NO2- + 2 Al + H2O + OH- >> NH3 + 2 AlO2-</span>
<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg
<em>Molar concentration
</em>
Assume you have 1 L solution.
Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)
= 1190 g solution
Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)
= 84.01 g NaHCO3
Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)
= 1.14 mol NaHCO3
<em>c</em> = 1.14 mol/1 L = 1.14 mol/L
<em>Molal concentration</em>
Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg
<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg
Answer:
Element Z
Explanation:
I hope this is correct and helps you!
Answer:
B
Explanation:
B
have cells with a cell wall and are heterotrophic
Answer:
C
Explanation:
because it remains the same
