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marshall27 [118]
3 years ago
5

the specific heat of aluminum is 0.897 j/g degrees celsius. if a 22.6 g sample of aluminum is heated from 25 degrees celsius to

250 degrees celcius then how much heat will the aluminum absorb?
Chemistry
1 answer:
Akimi4 [234]3 years ago
3 0
4,561.245 Joules
Q = Mass x Change in Temperature x Specific Heat 
Q = 22.6 x 225 x .897

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How many grams of phosphorus are in a sample of Ca3(PO4)2 that contains 50.0 g of calcium? Answer: ________ grams of phosphorus.
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<u>Answer:</u> The mass of phosphorus that is present for given amount of calcium is 28.53 g.

<u>Explanation:</u>

We are given:

Mass of calcium = 50 grams

The chemical formula of calcium phosphate is Ca_3(PO_4)_2

Molar mass of calcium = 40 g/mol

Molar mass of phosphorus = 31 g/mol

In 1 mole of calcium phosphate, 120 grams of calcium is combining with 62 grams of phosphorus.

So, 50 grams of calcium will combine with = \frac{62}{120}\times 50=28.53g of phosphorus.

Hence, the mass of phosphorus that is present for given amount of calcium is 28.53 g.

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Answer:

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A solution of zinc nitrate is added to a solution of magnesium sulfate. express your answer as a chemical equation. identify all
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Answer is: no reaction occurs, because all salts are soluble in water.

Balanced chemical reaction:  

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Ionic reaction:  

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8 0
3 years ago
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3 years ago
Solid potassium chlorate (kclo3) decomposes into potassium chloride and oxygen gas when heated. how many moles of oxygen form wh
IrinaVladis [17]

Answer:

  • <u>0.665 mol of O₂.</u>

Explanation:

<u>1. Molecular chemical equation:</u>

  • 2 KClO₃(s) → 2 KCl(s) + 3 O₂(g)

<u>2. Mole ratios:</u>

  • 2 mol KClO₃ : 2 mol KCl : 3 mol O₂

<u>3. Number of moles of KClO₃</u>

  • Number of moles = mass in grams / molar mass

  • Molar mass of KClO₃ = 122.55 g/mol

  • Number of moles of KClO₃ = 54.3 g / 122.5 g/mol ≈ 0.44308 mol

<u>3. Number of moles of O₂</u>

As per the theoretical mole ratio 2 mol of KClO₃ produce 3 mol of O₂, then set up a proportion to determine how many  moles of O₂ will be produced from 0.44038 mol of KClO₃.

  • 3 mol O₂ / 2 mol KClO₃ = x / 0.44038 mol KClO₃

  • x = (3 / 2) × 0.44308 mol O₂ = 0.6646 mol O₂

Round to 3 significant figures: 0.665 mol of O₂ ← answer

3 0
3 years ago
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