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marshall27 [118]
3 years ago
5

the specific heat of aluminum is 0.897 j/g degrees celsius. if a 22.6 g sample of aluminum is heated from 25 degrees celsius to

250 degrees celcius then how much heat will the aluminum absorb?
Chemistry
1 answer:
Akimi4 [234]3 years ago
3 0
4,561.245 Joules
Q = Mass x Change in Temperature x Specific Heat 
Q = 22.6 x 225 x .897

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A piece of material with a mass of 755 g is heated to 84.5 c and added to 50 g of water at 5
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Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
</span>so putting in your values is, 755g * ca * (75 celsius - 84.5 celsius) = -(50g * cb * (75 celsius - 5 celsius))
well we know the specific heat of water is always 4180J/kg celsius, so put that in for cb
with a bit of simplification to the equation by doing everything on each side first you have, -7172.5 * ca = -14630000
divide both sides by -7172.5 so you can single out ca and you get, ca= 2039.74
add units for specific heat which are J/kg celsius and the specific heat of the material is 2039.74 J/kg celsius

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brainly.com/question/1594044

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