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3 years ago

Sodium bromate chemical formula

Chemistry

2 answers:

Wewaii [24]3 years ago

6 0

NaBrO3 is the chemical formula for Sodium Bromate.

Alja [10]3 years ago

5 0

NaBrO3 is Sodium bromate chemical formula

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What is the ph of an aqueous solution with the hydronium ion concentration : [h3o+] = 3 x 10-5 m ?

BaLLatris [955]

The concentration of hydrogen can be shown as:

[H+ ] = 3 * 10-5 M

pH can be determined as:

pH = - log [H+ ]

= - log (3 * 10-5)

= 4.53

Thus the pH of solution is 4.53

8 0

3 years ago

Which of the following correctly represents the transmutation in which a curium-242 nucleus is bombarded with an alpha particle

Alekssandra [29.7K]

Answer: The chemical equation is written below.

Explanation:

Transmutation is defined as the process in which one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of curium-242 nucleus with alpha particle (helium nucleus) follows:

$_{96}^{242}\textrm{Cm}+_4^2\textrm{He}\rightarrow _{98}^{245}\textrm{Cf}+_0^1\textrm{n}$

The product formed in the nuclear reaction are californium-245 nucleus and a neutron particle.

6 0

3 years ago

Limiting Reactant Worksheet

faltersainse [42]

Answer:

a) 1.61 mol

b) Al is limiting reactant

c) HBr is in excess

Explanation:

Given data:

Moles of Al = 3.22 mol

Moles of HBr = 4.96 mol

Moles of H₂ formed = ?

What is limiting reactant =

What is excess reactant = ?

Solution:

Chemical equation:

2Al + 2HBr → 2AlBr + H₂

Now we will compare the moles:

Al : H₂

2 : 1

3.22 : 1/2×3.22 = 1.61 mol

HBr : H₂

2 : 1

4.96 : 1/2×4.96 = 2.48 mol

The number of moles of H₂ produced by Al are less it will be limiting reactant while HBr is present in excess.

Moles of H₂ :

Number of moles of H₂ = 1.61 mol

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2 years ago

A chemist prepares a solution of sodium thiosulfate by measuring out of sodium thiosulfate into a volumetric flask and filling t

marshall27 [118]

Mass of sodium thiosulfate $Na_{2}S_{2}O_{3}$ is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

$110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}}$ = 0.696 mol $Na_{2}S_{2}O_{3}$

Converting the volume of solution to L:

$350. mL * \frac{1 L}{1000 mL} = 0.350 L$

Finding out the concentration of solution in molarity:

$\frac{0.696 mol}{0.350 L} = 1.99 mol/L$

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3 years ago

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Sindrei [870]

AnswerIm telling your teacher "Ms.Byrd" your in 8th grade and go to berry middle?

Explanation:

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2 years ago