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mr Goodwill [35]
3 years ago
12

%:

Chemistry
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

I don't know the answer of this question.

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Determine the pH of a 0.05 M solution of hydrocyanic acid (HCN). Hydrocyanic acid has an acid-dissociation constant of 4.9 × 10-
KATRIN_1 [288]
The answer is 5.3. Just did it in e2020
7 0
3 years ago
Read 2 more answers
Please help with questions 7-12
Rufina [12.5K]

Answer:

negitive 5 or -5

Explanation

usally 12-7 = 5 but 7 is first so it you turn 5 to negitive 5

or -5

3 0
3 years ago
What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O
nadya68 [22]

Answer:

V=43.46mL

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4

Then, given the molarity, it is possible to obtain the milliliters as follows:

V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL

Best regards!

7 0
3 years ago
V 2 O 5 + Cl 2  VOCl 3 + O 2
rosijanka [135]

Answer: 3.5 moles V2O5

Explanation: First balance the chemical equation to find the stoichiometric factor between VOCl3 and V2O5

2 V2O5 + 6 Cl2 => 4 VOCl3 + 7 O2

So the mole to mole ratio is 2 moles V2O5 to 4 moles of VOCl3

Solution

7 moles VOCl3 x 2 moles V2O5 / 4 moles VOCl3 = 3.5 moles V2O5

5 0
3 years ago
Ice usually forms on the top part of lakes not the bottom , the reason for this occurence is?​
Bingel [31]

Answer:

Ice is less dense than water because of the way it forms a hexagonal crystalline structure. Each water molecule consists of two hydrogen atoms bonded to the bottom of an oxygen atom. ... In the winter, temperatures in a lake get close enough to freezing that the colder water is less dense and floats to the top

Explanation:

5 0
3 years ago
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